Question

我有一个JSP应用程序，允许用户上传ZIP文件，然后应用程序将读取ZIP中的所有文件并将它们存储在MySQL中。

根据建议，我决定使用“Zip文件系统提供程序”来处理ZIP文件：

Path zipPath = Paths.get(zipFile.getSubmittedFileName());//returns the path to the ZIP file
FileSystem fs = FileSystems.newFileSystem(zipPath, null);//creates the file system

我尝试使用以下方式遍历它：

for (FileStore store: fs.getFileStores()) {
         System.err.println("Store:  " + store.name());
}

然而，它只循环一次并返回tmp.zip这是整个ZIP。如何逐个提取物理图像文件，以便将它们存储在MySQL中。

Answer 1

这是遍历给定ZIP文件并在其中打印每个文件的前16个字节的代码。

{
    "count": 1,
    "results": [
        {
            "birthDate": "1990-07-11",
            "cardNumber": "0QBD0040267646",
            "cellPhone": "(514) 333-4444",
            "city": "Brossard",
            "email": "farouk.rahem@bciti.com",
        }
    ],
    "start": 0,
    "success": True,
    "total": 1
}

Answer 2

Apache Commons Compress 模块可能可以帮助您遍历文件。

下面是一个示例提取，可以迭代多个文件并提取字节内容样品

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package test;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
public class ZipTest {
    public static void main(String[] args) throws FileNotFoundException, IOException {
        String fileName = "C:\\temp\\ECDS-File-Upload-Processed.zip";
        String destinationDir = "C:\\temp\\mango";
        ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream(fileName));
        ZipEntry zipEntry = zipInputStream.getNextEntry();
        byte[] buffer = new byte[1024];
        while (zipEntry != null) {
            String zipFileName = zipEntry.getName();
            File extractedFile = new File(destinationDir + File.separator + zipFileName);
            new File(extractedFile.getParent()).mkdirs();
            FileOutputStream fos = new FileOutputStream(extractedFile);
            int len;
            while ((len = zipInputStream.read(buffer)) > 0) {
                fos.write(buffer, 0, len);
            }
            fos.close();
            zipEntry = zipInputStream.getNextEntry();
        }
        zipInputStream.closeEntry();
        zipInputStream.close();
    }
}

如何使用“Zip文件系统提供程序”遍历Java中的ZIP文件？

2 个答案: