我有三个领域对象。部门,部门和用户。 section是某个部门的一个子部门。但是每个部门和每个部门都会有用户。
@interface Department : RLMObject
@property NSString *name;
@property BOOL isCollapsed;
@property (nonatomic, strong) RLMArray<Section> *sections;
@property (nonatomic, strong) RLMArray<User> *users;
@end
@interface Section : RLMObject
@property NSString *name;
@property BOOL isCollapsed;
@property RLMArray<User> *users;
@end
@interface User : RLMObject
@property NSString *department;
@property NSString *email;
@property NSString *firstname;
@property NSString *lastname;
@property NSString *fullname;
@end
我想要做的是,我想搜索名字和姓氏包含的所有用户&#34; a&#34;并与部门和部门联系。
现在我正在做的是
searchText = [searchText lowercaseString];
RLMResults *sections = [Section objectsWhere:
[NSString stringWithFormat:@"SUBQUERY(users, $user, $user.fullname contains '%@' OR $user.nickname contains '%@').@count > 0",searchText,searchText]];
NSMutableArray *sectionNames = [NSMutableArray array];
for (Section *section in sections)
{
[sectionNames addObject:section.name];
}
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(sections, $section, $section.name IN %@).@count > 0", sectionNames];
RLMResults *filteredDepartments = [[Department objectsWithPredicate:predicate] sortedResultsUsingProperty:@"name" ascending:YES];
NSPredicate *pred = [NSPredicate predicateWithFormat:@"SUBQUERY(users, $user, $user.fullname contains %@ OR $user.nickname contains %@).@count > 0",searchText,searchText];
RLMResults *departments = [filteredDepartments objectsWithPredicate:pred];
目前问题是部分数组中有两个部分,但在部署结果中,它返回null。请帮忙。谢谢。
注意:如果一个用户已经属于某个部分,那么该用户将不会包含在部门中。
答案 0 :(得分:3)
也许您不需要使用子查询。更简单地说,您可以在查询中使用ANY
,如下所示:
[Department objectsWhere:
@"ANY users.firstname CONTAINS %@ OR ANY users.lastname CONTAINS %@ OR ANY sections.users.firstname CONTAINS %@ OR ANY sections.users.lastname CONTAINS %@", searchText, searchText, searchText, searchText];
但我认为使用反向关系更容易。在Realm中,反向关系定义为RLMLinkingObjects
。
您可以按如下方式向User
类添加反向关系:
@interface User : RLMObject
...
@property (readonly) RLMLinkingObjects *departments;
@property (readonly) RLMLinkingObjects *sections;
@end
@implementation User
+ (NSDictionary *)linkingObjectsProperties {
return @{@"departments": [RLMPropertyDescriptor descriptorWithClass:Department.class propertyName:@"users"],
@"sections": [RLMPropertyDescriptor descriptorWithClass:Section.class propertyName:@"users"]};
}
@end
然后,您可以从User
的属性获取用户所属的部门和部分,如下所示:
RLMResults *users = [User objectsWhere:@"firstname CONTAINS %@ OR lastname CONTAINS %@" , searchText, searchText];
for (User *user in users) {
NSLog(@"%@", user.departments);
NSLog(@"%@", user.sections);
}