Question

假设我有一个这样的字典

origin_dict={0:[],1:[],2:['bus'],3:['bus'],4:['bus'],5:[],6:[],7:['train'],8:['train'],9:['train'],10:[],11:[],12:['train'],13:['train'],14:[]}

我想用相同的值对它们进行分组，但只有当它们连续时。

new_dict={0:{2:'bus',3:'bus',4:'bus'},1:{7:'train',8:'train',9:'train'},2:{12:'train',13:'train'}}

任何人都有任何想法？

Answer 1

from collections import defaultdict
from operator import itemgetter
from itertools import groupby

origin_dict = {0: [], 1: [], 2: ['bus'], 3: ['bus'], 4: ['bus'], 5: [], 6: [], 7: [
    'train'], 8: ['train'], 9: ['train'], 10: [], 11: [], 12: ['train'], 13: ['train'], 14: []}

result = defaultdict(list)
for k, v in origin_dict.iteritems():
    key = "".join(sorted(v))
    if key != "":
        result[key].append(k)

solution = defaultdict(dict)
index = 0
for k, data in result.iteritems():
    for k1, g in groupby(enumerate(data), lambda (i, x): i - x):
        for v2 in map(itemgetter(1), g):
            solution[index][v2] = k
        index += 1

print origin_dict
print dict(solution)

Answer 2

这是我的简单而有效的解决方案。

if [[ "$(adb shell dumpsys wifi | grep mAirplaneModeOn)" == "mAirplaneModeOn true" ]]; then  

    adb shell am start -a android.settings.AIRPLANE_MODE_SETTINGS
        && input keyevent 19
        && input keyevent 23
        && input keyevent 4
fi

在字典中对相同的值进行分组并为每个值分配一个标记（或将它们分配到新的字典中）

2 个答案: