Question

我希望cronjob函数将所有allusers2的钱更新为1，而只增加第一行并增加9.（有10个用户）。我尝试将for循环换成for循环并得到相同的结果。我尝试将$ database-＆gt; fetch转换为mysqli_fetch_array并使用相同的结果并将其转换为mysqli_fetch_all，这给了我＆＃34;注意：未定义的索引：//变量名称＆＃34;对于所有数据库变量。

class allusers2
{
    public $id;
    public $level;
    public $money;
    private $database;

    // Methods (functions)
    public function __construct($allusers_id, $database)
    {
        $this->database = $database;
        $allusers_id = (int)$allusers_id;
        $result = $this->database->query("SELECT * FROM `users` WHERE `id`='$allusers_id'");
        if($this->database->num_rows($result) == 0) {
            throw new Exception("allusers does not exist!");
        }

        $allusers = $this->database->fetch($result);

        $this->id = $allusers['id'];
        $this->level = $allusers['level'];
        $this->money = $allusers['money'];

    }

    public function update()
    {

        $this->database->query("UPDATE `users` SET
            `level` = '{$this->level}',
            `money` = '{$this->money}'
            WHERE `id`='{$this->id}'");
    }
}

function cronjob()
{
    global $database;
    global $player;
    global $self_link;
    require('allusers2.php');
    $result = $database->query("SELECT id FROM `users`");
    $allusers_id = $database->fetch($result);
    $allusers2 = new Allusers2($allusers_id, $database);
    while($allusers_id = $database->fetch($result)) {

        $allusers2->money += 1;
        $allusers2->update();
    }
}

Answer 1

如果您确实要更新所有记录，并将金额增加相同金额，那么您不需要先选择记录并循环遍历它们 - 数据库可以执行一次性适合你：

UPDATE users SET money = money + 1

Answer 2

您只会更新第一位用户：

$result = $database->query("SELECT id FROM `users`");
$allusers_id = $database->fetch($result); // Extract the first user
$allusers2 = new Allusers2($allusers_id, $database); // Create object for first user
while($allusers_id = $database->fetch($result)) {

    $allusers2->money += 1; // Keep updating that first user
    $allusers2->update();
}

你需要不进行第一次获取，并将Allusers2移动到循环中：

   while($allusers_id = $database->fetch($result)) {

        $allusers2 = new Allusers2($allusers_id, $database); // Now you're creating a new object for each user
        $allusers2->money += 1;
        $allusers2->update();
    }

php while循环只更新第一行结果

2 个答案: