Question

我有两张桌子（联系人和电子邮件地址），我想知道是否有任何重复，无论是第一个名字还是姓氏或电子邮件地址，但我不确定这是否能让我得到我想要的东西？

＆＃13;

DECLARE @lClientId int;
SET @lClientId = @ClientId;

WITH Dups
AS (
		SELECT C.ClientId
			   ,C.FirstName
			   ,C.LastName
			   ,EA.Email
			   ,C.ContactId
			   ,C.IsDeleted
		FROM   Contacts C
			LEFT JOIN EmailAddresses EA
				ON EA.ParentId = C.ContactId
		WHERE C.ClientId = @ClientId	
	)
SELECT Dups1.ContactId
FROM Dups
	INNER JOIN Dups Dups1
		ON Dups1.ClientId = Dups.ClientId
		AND Dups1.FirstName = Dups.FirstName
		AND Dups1.LastName = Dups.LastName
		OR Dups1.Email = Dups.Email
WHERE	Dups.IsDeleted = 0

＆＃13;

Answer 1

对于像这样的测试数据

Firstname  lastname   email
 a          a1        smp
 a          a1        bmp
 c           d        dmp
 c          e         dmp

复制的输出将为..，您可以通过更改顺序来获取确定性数据

 a a1 smp
  c e dmp

DECLARE @lClientId int;
SET @lClientId = @ClientId;

WITH Dups
AS (
        SELECT C.ClientId
               ,C.FirstName
               ,C.LastName
               ,EA.Email
               ,C.ContactId
               ,C.IsDeleted
                Row_number() over (partition by firstname,lastname order by(select null)) as fnamerownum,
 Row_number() over (partition by email order by(select null)) as emailrownum
        FROM   Contacts C
            LEFT JOIN EmailAddresses EA
                ON EA.ParentId = C.ContactId
        WHERE C.ClientId = @ClientId
)
select * from dups
where fnamerownum>1 or emailrownum>1

Answer 2

如果你想要重复的第一个+姓氏或电子邮件列表

你可以

SELECT    C.FirstName
        , C.LastName
        , EA.Email
        , count(*)
    FROM   Contacts C
        LEFT JOIN EmailAddresses EA
            ON EA.ParentId = C.ContactId
group by   C.FirstName
         , C.LastName
         , EA.Email
having count(*) > 1

检查表中的重复项

2 个答案: