GetNumberFormat返回非英语域的垃圾值

Question

我正在使用GetNumberFormat函数来获取格式化的数字，但它返回非英语语言环境的垃圾值。

它适用于英语语言环境。

代码：

int FormatNumber(double number, long nbrDecs, char* destBuf, int bufSize)
{
char        infoBuf[3];
char        decimalSep[10];
char        thousandSep[10];
char        sourceNbr[50];
NUMBERFMT*  customFormat = NULL;
UINT        defDigits;
LCID        lcid;
int         status;

lcid = GetUserDefaultLCID();

status = GetLocaleInfo(lcid, LOCALE_IDIGITS, infoBuf, 3);
if (status == 0){
    return status;
}

defDigits =  atoi(infoBuf);
if (defDigits != (UINT) nbrDecs){
    customFormat = new NUMBERFMT;

    customFormat->NumDigits = nbrDecs;

    status = GetLocaleInfo(lcid, LOCALE_ILZERO, infoBuf, 3);
    customFormat->LeadingZero = atoi(infoBuf);

    status = GetLocaleInfo(lcid, LOCALE_SGROUPING, infoBuf, 3);
    customFormat->Grouping = atoi(infoBuf);

    status = GetLocaleInfo(lcid, LOCALE_STHOUSAND, thousandSep, 10);
    customFormat->lpThousandSep = thousandSep;

    status = GetLocaleInfo(lcid, LOCALE_SDECIMAL, decimalSep, 10);
    customFormat->lpDecimalSep = decimalSep;

    status = GetLocaleInfo(lcid, LOCALE_INEGNUMBER, infoBuf, 3);
    customFormat->NegativeOrder = atoi(infoBu`enter code here`f);
}

sprintf_s(sourceNbr, sizeof(sourceNbr),"%f", number)
status = GetNumberFormat(lcid, 0, sourceNbr, customFormat, destBuf,     bufSize);
// here destBuf is having the junk value. 

if (customFormat != NULL)
    delete customFormat;

return status; 
}

我正在获得垃圾价值。这里destBuf返回垃圾值。