Spring Security(Java配置)问题

时间:2016-08-10 14:46:45

标签: java security spring-security spring-4 userdetailsservice

大家好,

我有一个任务,我必须创建3个页面: / login - 我们有电子邮件和密码输入, / result - 我们必须告诉用户他是否已经授权,如果成功,我们可以显示第3页 - / dataEntry 我们可以在DataBase中保存或更新用户的信息。

典型项目的区别在于用户电子邮件和密码在USERS.XML中,而不在数据库(DB)中

我已经通过 sax dom 解析了它。

Parser返回 HashMap ,其中&#39; &#39;是&#39; 电子邮件&#39; <&#39; &#39;是&#39; 密码&#39;。

比我做默认域:

1) Login.class - 是auth的主要类,仅适用于users.xml。 它有下一个字段:电子邮件,密码。

2) User.class - 使用DB(保存,更新,加载用户信息)。它有下一个字段:id,email,firstName,secondName,gender。

接下来,我执行了此域的 dao service 图层。 在我问的底部,我会给bitbucket一个链接,但请你仔细阅读我的问题。

我通过Java配置项目,所以我做了 Hibernate配置(它工作正常), Web配置(看起来它也能正常工作)和安全配置(此刻我想开始哭泣)。

我的安全配置:

SecurityWebApplicationInitializer

public class SecurityWebApplicationInitializer extends AbstractSecurityWebApplicationInitializer {
public SecurityWebApplicationInitializer() {
}

SecurityConfiguration

public class SecurityConfiguration extends WebSecurityConfigurerAdapter {

/**
 * Holds userDetailsService
 */
@Autowired
@Qualifier("customUserDetailsService")
UserDetailsService userDetailsService;

/**
 * Gets BCryptPasswordEncoder object.
 *
 * @return BCryptPasswordEncoder object.
 */
@Bean
public PasswordEncoder passwordEncoder() {
    return new BCryptPasswordEncoder();
}

/**
 * Gets DaoAuthenticationProvider with its parameters
 *
 * @return authenticationProvider
 */
@Bean
public DaoAuthenticationProvider authenticationProvider() {
    DaoAuthenticationProvider authenticationProvider = new DaoAuthenticationProvider();
    authenticationProvider.setUserDetailsService(userDetailsService);
    authenticationProvider.setPasswordEncoder(passwordEncoder());
    return authenticationProvider;
}

/**
 * Sets GlobalSecurity parameters.
 *
 * @param auth - AuthenticationManagerBuilder object.
 * @throws Exception
 */
@Autowired
public void configureGlobalSecurity(AuthenticationManagerBuilder auth) throws Exception {
    auth.authenticationProvider(authenticationProvider());
}

/**
 * Sets Encoding parameters to work with russian locale, filters to get access to any page.
 * /index is login and logout page by default - everybody can open this page.
 * /result is page with results of login - everybody can open this page.
 * /dataEntry is page to save/update/load user's info - only registered user can open this page.
 *
 * @param http - {@link HttpSecurity} object
 * @throws Exception
 */
@Override
public void configure(HttpSecurity http) throws Exception {
    //To work with UTF-8 and RU locale
    CharacterEncodingFilter f = new CharacterEncodingFilter();
    f.setEncoding("UTF-8");
    f.setForceEncoding(true);

    http
            .addFilterBefore(f, CsrfFilter.class)
            .formLogin().loginPage("/index").defaultSuccessUrl("/result")
            .usernameParameter("email").passwordParameter("password")
            .and().logout().logoutSuccessUrl("/index").invalidateHttpSession(true)
            .and().httpBasic().realmName("ArtezioWebApp")
            .and().authorizeRequests()
            .antMatchers("/", "/index", "/result/**").permitAll()
            .antMatchers("/result/**").hasAnyAuthority("ROLE_USER","ROLE_ANONYMOUS")
            .antMatchers("/dataEntry/**").hasAuthority("ROLE_USER")
            .and().csrf()
            .and().exceptionHandling().accessDeniedPage("/result?error");
}

CustomUserDetailsS​​ervice

public class CustomUserDetailsService implements org.springframework.security.core.userdetails.UserDetailsService {

/**
 * Holds logger.
 */
private static final Logger logger = LoggerFactory.getLogger(CustomUserDetailsService.class);

/**
 * Holds {@link LoginService} object
 */
@Autowired
@Qualifier("loginService")
private LoginService loginService;

@Autowired
@Qualifier("login")
Login login;

/**
 * Gets UserDetailsService object with parameters - email, password, authorities.
 *
 * @param email - by default has alias 'userName'
 * @return UserDetailsService object with email,password and authorities.
 * @throws UsernameNotFoundException if user was not found in *.xml file.
 */
@Override
public UserDetails loadUserByUsername(String email) throws UsernameNotFoundException {
    //All users emails and passwords
    HashMap<String, String> h = loginService.getUsers();
    logger.info("Searching user with email '{}'...", email);

    if (loginService.isValidEmail(email)) {
        logger.info("User with email '{}' was found.", email);

        List<GrantedAuthority> authorities = new ArrayList<>();
        authorities.add(new SimpleGrantedAuthority("ROLE_USER"));

        //Saves data in Login object
        login.setPassword(h.get(email));
        login.setEmail(email);
        return new org.springframework.security.core.userdetails.User(login.getEmail(),
                login.getPassword(), true, true, true, true, authorities);
    }
    throw new UsernameNotFoundException("User with email '" + email + "' not found.");
}

当我调试项目时,我注意到永远不会调用@Overloaded方法loadByUsername(String email)。

SecurityContext返回anonymusUser,即使我输入了正确的电子邮件和密码。 所以我无法访问/ dataEntry页面。

链接到BITBUCKET:Bitbucket

有人请帮助我。 非常感谢。

1 个答案:

答案 0 :(得分:0)

需要将login-processing-url添加为“/ j_spring_security_check”才能工作,并在登录表单上添加“j_spring_security_check”操作。 在此处阅读更多内容:Spring migration