此应用程序向返回数据的API发送请求。我想将该数据保存到xml文件。 问题是,每次运行应用程序时,我都想创建一个新的xml文件,而不是替换当前的“c:\ temp \ xml.xml”。我希望它们能够按当前日期命名,而不是1 xml.xml我想要20160810.xml,第二天当我运行应用程序时,我想要另一个名为20160811.xml的xml文件。我该怎么做?
static void Main(string[] args)
{
RunAsync().Wait();
}
static async Task RunAsync()
{
using (var client = new HttpClient())
{
//Send HTTPrequest
client.BaseAddress = new Uri("http://xxxxx");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
HttpResponseMessage response = await client.GetAsync("api/people/peoples?Firstname=Adam");
if (response.IsSuccessStatusCode)
{
var person = response.Content.ReadAsAsync<IEnumerable<Persons>>().Result;
XmlDocument xmldoc = new XmlDocument();
foreach (var i in person)
{
XmlElement el = (XmlElement)xmldoc.AppendChild(xmldoc.CreateElement("Employee"));
el.SetAttribute("EmployeeID", i.Peopleid);
el.AppendChild(xmldoc.CreateElement("Firstname")).InnerText = i.FirstName;
el.AppendChild(xmldoc.CreateElement("Lastname")).InnerText = i.LastName;
el.AppendChild(xmldoc.CreateElement("Address")).InnerText = i.LocationName;
Console.WriteLine("{0}\t{1}:\t{2}\t-{3}", i.FirstName, i.LastName, i.Peopleid, i.LocationName );
xmldoc.Save("c:\\temp\\xml.xml");
}
}
}
}
class Persons
{
public string Peopleid { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public string LocationName { get; set; }
}
答案 0 :(得分:0)
DateTime.Now提供当前日期和时间,因此请将保存修改为
xmldoc.Save("c:\\temp\\"+DateTime.Now.ToString("yyyyMMdd") + ".xml");