Question

我有2张桌子 1.Org [ORG_ID，PARENT_ID，LANG_ID（REFERENCES LANG）] 2.Lang [LANG_ID，LANG_NAME]

我的JAVA实体文件

Lang.java

@Entity
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "langId")
@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
@SuppressWarnings("serial")
public class Lang implements java.io.Serializable {
    private BigDecimal langId;
    private String langName;
    private Set<Org> orgs = new HashSet<Org>(0);
    public Lang() {
    }
    public Lang(BigDecimal langId, Set<Org> orgs) {
        this.langId = langId;
        this.orgs = orgs;
    }
    public BigDecimal getLangId() {
        return this.langId;
    }
    public void setLangId(BigDecimal langId) {
        this.langId = langId;
    }
    public String getLangName() {
        return this.langName;
    }
    public void setLangName(String langName) {
        this.langName = langName;
    }public void setOrgs(Set<Org> orgs) {
        this.orgs = orgs;
    }
}

Org.java

    @Entity
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "orgId")
@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
@SuppressWarnings("serial")
public class Org implements java.io.Serializable {
    @Id
    @Column(name = "orgId")
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private BigDecimal orgId;   
    private BigDecimal parentOrgId;
    @JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "langId",scope=Lang.class)
    public Org() {
    }
    public Org(BigDecimal orgId, BigDecimal parentOrgId, Lang lang) {
        this.orgId = orgId;
        this.parentOrgId = parentOrgId;
        this.lang = lang;
    }
    public BigDecimal getOrgId() {
        return this.orgId;
    }
    public void setOrgId(BigDecimal orgId) {
        this.orgId = orgId;
    }
    public BigDecimal getParentOrgId() {
        return this.parentOrgId;
    }
    public void setParentOrgId(BigDecimal parentOrgId) {
        this.parentOrgId = parentOrgId;
    }
    @ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
    public Lang getLang() {
        return this.lang;
    }
    public void setLang(Lang lang) {
        this.lang = lang;
    }
}

我的HBM Xml文件

Org.hbm.xml

    <hibernate-mapping package="com.test.entity">
    <class name="com.test.entity.Org" table="ORG">
    <id name="orgId" type="big_decimal">
        <column name="ORG_ID" precision="22" scale="0" />
        <generator class="increment" />
    </id>        
    <property name="parentOrgId" type="big_decimal">
        <column name="PARENT_ORG_ID" precision="22" scale="0" not-null="true" />
    </property>
    <many-to-one name="lang" class="com.test.entity.Lang" fetch="select">
        <column name="LANG_ID" precision="22" scale="0" not-null="true" />
    </many-to-one>        
    </class>
</hibernate-mapping>

Lang.hbm.xml

    <hibernate-mapping package="com.test.entity">
    <class name="com.test.entity.Lang" table="LANG">
    <id name="langId" type="big_decimal">
        <column name="LANG_ID" precision="22" scale="0" />
        <generator class="increment" />
    </id>
    <property name="langName" type="string">
        <column name="LANG_NAME" length="32" not-null="true" unique="true" />
    </property>
    <set name="orgs" table="ORG" inverse="true" lazy="true" fetch="select">
        <key>
        <column name="LANG_ID" precision="22" scale="0" not-null="true" />
        </key>
        <one-to-many class="com.test.entity.Org" />
    </set>
    </class>
</hibernate-mapping>

我的Hibernate查询是：＆＃34; FROM Org as org WHERE org.parentOrgId =：parentOrgId org.orgId =：parentOrgId＆＃34;
DataBase
当我从控制器运行时列表listOrganization = organizationService.getAllChildWithParetOrgs（parentId）; // parentId = 0

我得到了结果ObjectList / JSON Result

    [
  {
    "orgId": 1,
    "parentOrgId": 0,    
    "lang": {
      "langId": 1,
      "langName": "EN",
      "orgs": [
    {
      "orgId": 2,
      "parentOrgId": 1,
      "lang": 1,
      "currency": {
        "currencyId": 1,
        "currencyCode": "INR",
        "currencyName": "INR",
        "currencyDescription": "INDIAN RUPEE",
        "orgs": [
          2,
          1,
          {
        "orgId": 3,
        "parentOrgId": 1,
        "lang": 1,
        "currency": 1,                
          }
        ]
      }
    },
    1,
    3
      ]
    },
    "currency": 1
  },
  2, //---> Here No 2nd Organization Data
  3  //---> Here No 3rd Organization Data
]

此处货币也与 Lang 表相同，其Currency_Id参考货币
我无法获得第二名＆amp;数组中的第三个组织数据，它在Lang.Orgs和Lang.Orgs.Currency中可用
请帮忙。谢谢。

Answer 1

请提供您的Controller方法getAllChildWithParetOrgs(parentId);的代码。那会更有帮助。另外，根据我对hibernate查询连接和数据库快照的理解，我不认为JSON输出应该再次登记记录。请在下面找到解释：

由于您传递的parentId为0.并且基于hibernate查询连接和数据库快照，似乎 OrgId = 0 没有单独的记录。从子句的 parentOrgId = 0 部分开始，它指的是子：orgId为1的记录。随后，它指的是 orgId = 1 的子记录，即 parentOrgId = 1 的记录，这些记录是 orgId = 2 ＆amp; orgId = 3 。我不认为你的JSON对象应该在那之后再获得更多的结果

Hibernate @ManyToOne和@OneToMany将数据作为List（记录数）获取

1 个答案: