Question

我在其他帖子中搜索过，但没有找到解决问题的方法。

我读了一个文件的内容，我需要在20秒后再次查看它是否已被更改。

我使用了threading.Timer，threading.Thread with time.sleep，threading.Event with wait（）and Queue - 但每次它都阻塞所有线程，所以文件在等待期间不会被修改，而是在之后。

如何让其他功能修改文件并在20秒后检查更改？

代码：

def function1():
    counter = open('textfile.txt', 'r').read()
    result = received_msg(counter)
    return result

def received_msg(counter):
    import time
    time.sleep(20)

    with open('textfile1.txt', 'r') as c:
        newcounter = c.read()
        c.close()

        if newcounter != counter:
            with open('textfile2', 'r') as msgs:
                lines = msgs.readlines()
                msgs.close()

                if lines:
                    last_line = lines[-1]

                    return last_line

        else:
            return "No changes"

这里修改文件的功能：

def inbound():
    if request.form.get('token') == TOKEN:
        text = request.form.get('text')

        counter = open('textfile.txt', 'r').read()

        with open('textfile2.txt', 'a+') as msgs:
            msgs.write(text+'\n')
            msgs.close()

        with open('textfile.txt', 'w+') as c2:
            newcounter = int(float(counter)) + 1
            c2.write(str(newcounter))
            c2.close()

    return Response(), 200

带线程的版本：

def function1():
    import threading, Queue
    q = Queue.Queue()
    counter = open('textfile.txt', 'r').read()
    threading.Timer(20, received_msg, [counter, q]).start()
    result = q.get()
    return result

def received_msg(counter):

    with open('textfile1.txt', 'r') as c:
        newcounter = c.read()
        c.close()

        if newcounter != counter:
            with open('textfile2', 'r') as msgs:
                lines = msgs.readlines()
                msgs.close()

                if lines:
                    last_line = lines[-1]

                    q.put(last_line)

        else:
            q.put("No changes")

python - 线程睡眠阻止所有线程

0 个答案: