Question

我正在导入交易数据并将其保存到数据库中。某些事务数据缺少字段，因此我使用以下函数从单独的文件（file2.php）手动更新它们：

function categoryRules() {
    //rules for transactions
    $sql = "UPDATE Transactions 
                SET cat1 = 'Shops', cat2 = 'Supermarkets and Groceries'
            WHERE name LIKE '%shipt%'";
    if (mysqli_query($conn, $sql)) {
        echo "SHIPT UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }   
    $sql = "UPDATE Transactions 
                SET cat1 = 'Shops', cat2 = 'Food and Beverage Store', cat3 = 'Beer, Wine and Spirits'
            WHERE name LIKE '%liquor%'";
    if (mysqli_query($conn, $sql)) {
        echo "LIQUOR UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }
    $sql = "UPDATE Transactions 
                SET cat1 = 'Service', cat2 = 'Telecommunication Services'
            WHERE name LIKE '%vzwrls%'";
    if (mysqli_query($conn, $sql)) {
        echo "VERIZON UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }

    $sql = "UPDATE Transactions 
                SET cat1 = 'Recreation', cat2 = 'Gyms and Fitness Centers'
            WHERE name LIKE '%classpass%'";
    if (mysqli_query($conn, $sql)) {
        echo "VERIZON UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }
}

要在file1.php中清理我的代码，我在文件1.php上调用file2函数：

$conn = mysqli_connect($host, $user, $pass, $database);
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
include 'categoryRules.php';
categoryRules();
mysqli_close($conn);

这样做时我得到以下回复：

错误：UPDATE Transactions SET cat1 =＆＃39; Shops＆＃39;，cat2 =＆＃39;超市   和杂货＆＃39;名称LIKE＆＃39;％shipt％＆＃39;

错误：UPDATE Transactions SET cat1 =＆＃39; Shops＆＃39;，cat2 =＆＃39;超市和杂货＆＃39;名称LIKE＆＃39;％shipt％＆＃39;

错误：更新交易SET cat1 =＆＃39;商店＆＃39;，cat2 =＆＃39;食品和饮料商店＆＃39;，cat3 =＆＃39;啤酒，葡萄酒和烈酒＆＃39;名称喜欢＆％39％％％＆＃39;

错误：更新交易SET cat1 =＆＃39;服务＆＃39;，cat2 =＆＃39;电信服务＆＃39;名称喜欢＆＃39;％vzwrls％＆＃39;

错误：UPDATE Transactions SET cat1 =＆＃39; Recreation＆＃39;，cat2 =＆＃39;健身房和健身中心＆＃39;名称LIKE＆＃39;％classpass％＆＃39;

似乎函数可能在文件2.php中运行，然后才到达file1.php，这是我打开，访问和关闭数据库链接的地方。有没有办法将它们导入文件1？除了创建文件2.php之外，还有更好的方法来清理文件1.php的这部分代码吗？

Answer 1

啊，当然，我应该早点想到这个

您在函数外部建立了连接，因此$conn在函数内部不可见，只需将$conn作为参数传递给函数，它就会神奇地起作用。这是一个简单的范围问题！

categoryRules.php

function categoryRules($conn) {    // <-- add parameter
    //rules for transactions
    $sql = "UPDATE Transactions 
                SET cat1 = 'Shops', cat2 = 'Supermarkets and Groceries'
            WHERE name LIKE '%shipt%'";
    if (mysqli_query($conn, $sql)) {
        echo "SHIPT UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }   
    $sql = "UPDATE Transactions 
                SET cat1 = 'Shops', cat2 = 'Food and Beverage Store', cat3 = 'Beer, Wine and Spirits'
            WHERE name LIKE '%liquor%'";
    if (mysqli_query($conn, $sql)) {
        echo "LIQUOR UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }
    $sql = "UPDATE Transactions 
                SET cat1 = 'Service', cat2 = 'Telecommunication Services'
            WHERE name LIKE '%vzwrls%'";
    if (mysqli_query($conn, $sql)) {
        echo "VERIZON UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }

    $sql = "UPDATE Transactions 
                SET cat1 = 'Recreation', cat2 = 'Gyms and Fitness Centers'
            WHERE name LIKE '%classpass%'";
    if (mysqli_query($conn, $sql)) {
        echo "VERIZON UPDATE PERFORMED";
    } else {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }
}

现在主要脚本应该是

$conn = mysqli_connect($host, $user, $pass, $database);
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
include 'categoryRules.php';
// add $conn parameter to the call
categoryRules($conn);           
mysqli_close($conn);

从另一个php文件调用mysqli函数

1 个答案: