Question

是否可以以编程方式读取lambda引用的类和静态方法名称？例如：

R version 3.3.0 (2016-05-03)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows 7 x64 (build 7601) Service Pack 1

locale:
[1] LC_COLLATE=English_United States.1252 
[2] LC_CTYPE=English_United States.1252   
[3] LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C                          
[5] LC_TIME=English_United States.1252    

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base     

other attached packages:
[1] rworldmap_1.3-6 sp_1.2-3        RSQLite_1.0.0   DBI_0.4-1      

loaded via a namespace (and not attached):
[1] foreign_0.8-66  fields_8.4-1    maps_3.1.0      maptools_0.8-39
[5] grid_3.3.0      spam_1.3-0      lattice_0.20-33

我想以某种方式阅读R version 3.1.1 (2014-07-10) Platform: x86_64-w64-mingw32/x64 (64-bit) locale: [1] LC_COLLATE=English_United States.1252 [2] LC_CTYPE=English_United States.1252 [3] LC_MONETARY=English_United States.1252 [4] LC_NUMERIC=C [5] LC_TIME=English_United States.1252 attached base packages: [1] stats graphics grDevices utils datasets methods base other attached packages: [1] rworldmap_1.3-6 sp_1.0-15 RSQLite_0.11.4 DBI_0.3.1 loaded via a namespace (and not attached): [1] fields_8.3-6 foreign_0.8-61 grid_3.1.1 lattice_0.20-29 [5] maps_2.3-9 maptools_0.8-30 spam_1.3-0指向public class Testing { interface Generic { void call(); } static public void method1() { System.out.println("In method1"); } static public void method2() { System.out.println("In method2"); } public void test() { Generic g1 = () -> Testing.method1(); Generic g2 = () -> Testing.method2(); g1.call(); g2.call(); // System.out.println("g1 -> " + getLambdaReference(g1)) }而g1指向Testing.method1。

Answer 1

没有这样的参考。那些lambda函数只是执行一些代码的Lambdas。

如果这些方法可行，那么你如何处理

Generics g = ()->1+2;

或任何其他只是表达式？

获取lambda引用的类和静态方法名称

1 个答案: