在此代码段中调用Nothing
的类型参数是get
怎么可能?在没有显式类型参数的情况下调用case class User(email: String)
object Hello {
def main(args: Array[String]): Unit = {
val store = new ObjectStore
store.get
}
}
class ObjectStore {
def get[A: Manifest]: Option[A] = {
println(manifest[A].toString())
None
}
}
时,如何强制编译器产生错误?
jsdom.env
答案 0 :(得分:2)
基于this blog post,以下内容应该有效:
@implicitNotFound("Nothing was inferred")
sealed trait NotNothing[-T]
object NotNothing {
implicit object notNothing extends NotNothing[Any]
implicit object `\n The error is because the type parameter was resolved to Nothing` extends NotNothing[Nothing]
}
class ObjectStore {
def get[T](implicit evManifest: Manifest[T], evNotNothing: NotNothing[T]): Option[T] = {
println(manifest[T].toString())
None
}
}
object X {
val oo = new ObjectStore().get[Any]
//fails to compile
//val o = new ObjectStore().get
}