Question

我有2个表，我正在尝试提取特定材料的记录。所以我的查询如下

单日查询

SELECT tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin, COUNT( product_serial_no ) AS  `S_FTD` 
FROM register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE retailer_code =  '9017'
AND register_product_claim.dt =  '2016-08-04'
GROUP BY tm.asin
ORDER BY register_product_claim.dt DESC 
LIMIT 0 , 30

月亮

SELECT tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin, COUNT( product_serial_no ) AS  `S_MTD` 
FROM register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE retailer_code =  '9017'
AND MONTH( register_product_claim.dt ) =  '08'
GROUP BY tm.asin
ORDER BY register_product_claim.dt DESC 
LIMIT 0 , 30

Qtr Wise

SELECT tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin, COUNT( product_serial_no ) AS  `S_QTD` 
FROM register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE retailer_code =  '9017'
AND (
MONTH( register_product_claim.dt ) =  '08'
OR MONTH( register_product_claim.dt ) =  '07'
OR MONTH( register_product_claim.dt ) =  '06'
)
GROUP BY tm.asin
ORDER BY register_product_claim.dt DESC 
LIMIT 0 , 30

一切正常。

现在我正在尝试合并所有查询。但我无法合并它们。联盟，加入，但没有运气。

最后一次尝试是

SELECT *
FROM 
    (SELECT 
        tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin,
        COUNT(product_serial_no) as S_FTD
    FROM
        register_product_claim
    INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
    WHERE
        retailer_code = '9017'
            AND register_product_claim.dt = '2016-08-04'
    GROUP BY tm.asin) as s1  
   Inner Join
    (SELECT 

        COUNT(product_serial_no) as S_MTD
    FROM
        register_product_claim
    INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
    WHERE
        retailer_code = '9017'
            AND MONTH(register_product_claim.dt) = '08'
    GROUP BY tm.asin) as s2
   Inner Join
    (SELECT 

        COUNT(product_serial_no) as S_QTD
    FROM
        register_product_claim
    INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
    WHERE
        retailer_code = '9017'
            AND (MONTH(register_product_claim.dt) = '08'
            OR MONTH(register_product_claim.dt) = '07'
            OR MONTH(register_product_claim.dt) = '06')
    GROUP BY tm.asin) as s3

我的预期输出是

model_number | item_description |  mrp | asin | S_FTD | S_MTD | S_QTD

当S_FTD为一天时，S_MTD为每月，S_QTD为季度结果。

Answer 1

您可以使用条件聚合来完成，将其调整为您的代码：

SELECT t.model_number,t.item_description,t.mrp,t.asin,
       MAX(CASE WHEN t.new_col = 'D' then t.S_TD END) as S_FTD,
       MAX(CASE WHEN t.new_col = 'M' then t.S_TD END) as S_MTD,
       MAX(CASE WHEN t.new_col = 'Q' then t.S_TD END) as S_QTD
FROM (
     SELECT ss.*,'D' as new_col FROM (Daily Query) ss
     UNION ALL
     SELECT ss1.*,'M' FROM (Monthly Query) ss1
     UNION ALL
     SELECT ss2.*,'Q' FROM (Quarter Query) ss2
     ) t
GROUP BY t.model_number,t.item_description,t.mrp,t.asin

注意：您必须将每日查询中的列S_FTD别名为S_TD才能生效。

Answer 2

尝试使用从* 中选择* 在每个表之前

eg.SELECT * FROM（从中选择* （选择 tm.internal_name AS model_number，tm.item_description，tm.mrp，tm.asin， COUNT（product_serial_no）为S_FTD 从 register_product_claim INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin 哪里 retailer_code = '9017' AND register_product_claim.dt ='2016-08-04' GROUP BY tm.asin）as s1
联盟

SELECT *
FROM (
     Select * from
    (SELECT 
        tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin,
        COUNT(product_serial_no) as S_FTD
    FROM
        register_product_claim
    INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
    WHERE
        retailer_code = '9017'
            AND register_product_claim.dt = '2016-08-04'
    GROUP BY tm.asin) as s1  
  Union

select * from


    (SELECT 

        COUNT(product_serial_no) as S_MTD
    FROM
        register_product_claim
    INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
    WHERE
        retailer_code = '9017'
            AND MONTH(register_product_claim.dt) = '08'
    GROUP BY tm.asin) as s2
 Union
Select * from
    (SELECT 

        COUNT(product_serial_no) as S_QTD
    FROM
        register_product_claim
    INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
    WHERE
        retailer_code = '9017'
            AND (MONTH(register_product_claim.dt) = '08'
            OR MONTH(register_product_claim.dt) = '07'
            OR MONTH(register_product_claim.dt) = '06')
    GROUP BY tm.asin) as s3

)

如何组合3个查询？

2 个答案: