Question

当其他人太忙时，线程不会启动

我有多线程应用程序。我正在分析两个线程的工作流程。 Thread_1的周期为for(...)。 Thread_2有一些小工作。在某些情况下Thread_2 for(...)未在Thread_1中完成周期Thread_1时，Thread_2无法启动它。系统是否可能决定为Thread_1放置所有资源？如何在for(...) Thread.sleep(100)期间启动-openmp的可能性。我应该把omp_get_thread_num放在那里吗？一切都在Java 1.4中。

Answer 1

如果你共享一些代码片段会很棒，但是如果不看逻辑就很难调试代码。理想情况下，thread_1和thread_2应该独立运行。 thread_2无法等待在thread_1中完成循环。例如：

class RunnableDemo implements Runnable {
   private Thread t;
   private String threadName;

   RunnableDemo( String name){
       threadName = name;
       System.out.println("Creating " +  threadName );
   }
   public void run() {
      System.out.println("Running " +  threadName );
      try {
         for(int i = 4; i > 0; i--) {
            System.out.println("Thread: " + threadName + ", " + i);
            // Let the thread sleep for a while.
            Thread.sleep(50);
         }
     } catch (InterruptedException e) {
         System.out.println("Thread " +  threadName + " interrupted.");
     }
     System.out.println("Thread " +  threadName + " exiting.");
   }

   public void start ()
   {
      System.out.println("Starting " +  threadName );
      if (t == null)
      {
         t = new Thread (this, threadName);
         t.start ();
      }
   }

}

public class TestThread {
   public static void main(String args[]) {

      RunnableDemo R1 = new RunnableDemo( "Thread-1");
      R1.start();

      RunnableDemo R2 = new RunnableDemo( "Thread-2");
      R2.start();
   }   
}

输出：

Creating Thread-1
Starting Thread-1
Creating Thread-2
Starting Thread-2
Running Thread-1
Thread: Thread-1, 4
Running Thread-2
Thread: Thread-2, 4
Thread: Thread-1, 3
Thread: Thread-2, 3
Thread: Thread-1, 2
Thread: Thread-2, 2
Thread: Thread-1, 1
Thread: Thread-2, 1
Thread Thread-1 exiting.
Thread Thread-2 exiting.

Answer 2

你可以在给定次数的迭代后使第一个线程循环暂停，并在Thread_2完成后将静态var th2_done设置为false而不是腰线Thread_1时间

Thread_1：         for（...）{             if（num_it％cycle＆amp;＆amp; th2_done == false）sleep（100）;}

Thread_2：for（...）{} th2_done = true

线程无法启动而其他线程太忙

2 个答案: