我有一个问题，我的第一个司机（PIT）的制作。在我之前记录的这个视频中清楚地解释了这个问题：https://www.youtube.com/watch?v=hjvTtVbaics&feature=youtu.be。让我先显示我的计时器驱动程序：
timer.c中++：
#include "timer.h"
/* This will keep track of how many ticks that the system
* has been running for */
typedef void(*regs_func)(struct regs *r);
static int32_t timer_ticks = 0;
extern void install_handler_irq(int irq, regs_func handler);
/* Handles the timer. In this case, it's very simple: We
* increment the 'Timer::timer_ticks' variable every time the
* timer fires. By default, the timer fires 18.222 times
* per second. Why 18.222Hz? Some engineer at IBM must've
* been smoking something funky */
void timer_handler_driver(struct regs *r)
{
/* Increment our 'tick count' */
timer_ticks++;
/* Every 18 clocks (approximately 1 second), we will
* display a message on the screen */
// if (timer_ticks % 18 == 0)
// {
printf("One second has passed\n");
// }
}
Timer::Timer()
{
}
/* This will continuously loop until the given time has
* been reached */
void Timer::timer_wait(int ticks)
{
unsigned long eticks;
eticks = timer_ticks + ticks;
while((unsigned)timer_ticks < eticks);
}
void Timer::install_timer()
{
install_handler_irq(0, timer_handler_driver);
}
/* Sets up the system clock by installing the timer handler
* into IRQ0 */
Timer::~Timer()
{
}
这是我的irq c ++代码：
irq.c ++：
#include "irq.h"
#define PIC_MASTER_CONTROL 0x20
#define PIC_MASTER_MASK 0x21
#define PIC_SLAVE_CONTROL 0xa0
#define PIC_SLAVE_MASK 0xa1
typedef void(*regs_func)(struct regs *r);
/*Get all irq's*/
extern "C" void irq0(void);
extern "C" void irq1(void);
extern "C" void irq2(void);
extern "C" void irq3(void);
extern "C" void irq4(void);
extern "C" void irq5(void);
extern "C" void irq6(void);
extern "C" void irq7(void);
extern "C" void irq8(void);
extern "C" void irq9(void);
extern "C" void irq10(void);
extern "C" void irq11(void);
extern "C" void irq12(void);
extern "C" void irq13(void);
extern "C" void irq14(void);
extern "C" void irq15(void);
extern void panic(const char* exception);
regs_func irq_routines[16] = {
0,0,0,0,0,0,0,0
,0,0,0,0,0,0,0,0
};
static PORT::Port8Bits p8b_irq;
static SerialPort sp_irq;
//Basically a declaration of IDT_ENTRY in
//idt.c++
struct idt_entry {
uint16_t base_lo;
uint16_t sel; // Kernel segment goes here.
uint8_t always0;
uint8_t flags; // Set using the table.
uint16_t base_hi;
}__attribute__((packed));
//Get the Exact IDT array from idt.c++
extern struct idt_entry idt[256];
static inline void idt_set_gate(uint8_t num, void(*handler)(void), uint16_t sel,
uint8_t flags)
{
idt[num].base_lo = (uintptr_t)handler >> 0 & 0xFFFF;
idt[num].base_hi = (uintptr_t)handler >> 16 & 0xffff;
idt[num].always0 = 0;
idt[num].sel = sel;
idt[num].flags = flags;
}
IRQ::IRQ(){};
IRQ::~IRQ(){};
/* Normally, IRQs 0 to 7 are mapped to entries 8 to 15. This
* is a problem in protected mode, because IDT entry 8 is a
* Double Fault! Without remapping, every time IRQ0 fires,
* you get a Double Fault Exception, which is NOT actually
* what's happening. We send commands to the Programmable
* Interrupt Controller (PICs - also called the 8259's) in
* order to make IRQ0 to 15 be remapped to IDT entries 32 to
* 47 */
void IRQ::irq_remap()
{
// ICW1 - begin initialization
p8b_irq.out(0x11,PIC_MASTER_CONTROL);
p8b_irq.out(0x11,PIC_SLAVE_CONTROL);
// Remap interrupts beyond 0x20 because the first 32 are cpu exceptions
p8b_irq.out(0x21,PIC_MASTER_MASK);
p8b_irq.out(0x28,PIC_SLAVE_MASK);
// ICW3 - setup cascading
p8b_irq.out(0x04,PIC_MASTER_MASK);
p8b_irq.out(0x02,PIC_SLAVE_MASK);
// ICW4 - environment info
p8b_irq.out(0x01,PIC_MASTER_MASK);
p8b_irq.out(0x01,PIC_SLAVE_MASK);
// mask interrupts
p8b_irq.out(0,PIC_MASTER_MASK);
p8b_irq.out(0,PIC_SLAVE_MASK);
}
void install_handler_irq(int irq, regs_func handler)
{
printf(" \n Installer IRQ %d \n ", irq);
irq_routines[irq] = handler;
}
void uninstall_handler_irq(int irq)
{
irq_routines[irq] = 0;
}
/* First remap the interrupt controllers, and then we install
* the appropriate ISRs to the correct entries in the IDT. This
* is just like installing the exception handlers */
void IRQ::install_irqs()
{
this->irq_remap();
idt_set_gate(32, irq0, 0x08, 0x8E);
idt_set_gate(33, irq1, 0x08, 0x8E);
idt_set_gate(34, irq2, 0x08, 0x8E);
idt_set_gate(35, irq3, 0x08, 0x8E);
idt_set_gate(36, irq4, 0x08, 0x8E);
idt_set_gate(37, irq5, 0x08, 0x8E);
idt_set_gate(38, irq6, 0x08, 0x8E);
idt_set_gate(39, irq7, 0x08, 0x8E);
idt_set_gate(40, irq8, 0x08, 0x8E);
idt_set_gate(41, irq9, 0x08, 0x8E);
idt_set_gate(42, irq10, 0x08, 0x8E);
idt_set_gate(43, irq11, 0x08, 0x8E);
idt_set_gate(44, irq12, 0x08, 0x8E);
idt_set_gate(45, irq13, 0x08, 0x8E);
idt_set_gate(46, irq14, 0x08, 0x8E);
idt_set_gate(47, irq15, 0x08, 0x8E);
}
/* Each of the IRQ ISRs point to this function, rather than
* the 'fault_handler' in 'isrs.c'. The IRQ Controllers need
* to be told when you are done servicing them, so you need
* to send them an "End of Interrupt" command (0x20). There
* are two 8259 chips: The first exists at 0x20, the second
* exists at 0xA0. If the second controller (an IRQ from 8 to
* 15) gets an interrupt, you need to acknowledge the
* interrupt at BOTH controllers, otherwise, you only send
* an EOI command to the first controller. If you don't send
* an EOI, you won't raise any more IRQs */
extern "C" void irq_handler(struct regs *r)
{
printf("IRQ Being Handled");
}
和我的irq.S：
.section .text
.extern irq_handler
.extern test_func
.macro irq number
.global irq\number
irq\number:
cli
pushl $0
pushl $\number
jmp common_handler_irq
.endm
common_handler_irq:
# save registers
pusha
# call C++ Handler
call irq_handler
# restore registers
popa
iret
#TODO FOR LOOP
irq 0
irq 1
irq 2
irq 3
irq 4
irq 5
irq 6
irq 7
irq 8
irq 9
irq 10
irq 11
irq 12
irq 13
irq 14
irq 15
在我开始之前，我的github就在这里，所以你可以看到我的整个代码：https://github.com/amanuel2/OS_Mirror。所以基本上是发生了什么。你可以在我的timer.c ++上看到，如果我有if语句注释它打印一秒传递和qemu上的错误（双错），如果我不打算打印任何东西和双重错误。你可以从viedo看到：[url] https://www.youtube.com/watch?v=hjvTtVbaics&feature=youtu.be[/url]。帮助会得到赞赏！
有时候它决定只在qemu上显示错误信息，并且根本就说一秒通过，或者甚至是Divide by 0错误，并给我这个：
qemu: fatal: Trying to execute code outside RAM or ROM at 0x491019d0
EAX=00000000 EBX=00009500 ECX=00000700 EDX=0010159e
ESI=00000000 EDI=00109000 EBP=00107122 ESP=001031ee
EIP=001019d0 EFL=00000002 [-------] CPL=0 II=0 A20=1 SMM=0 HLT=0
ES =0010 00000000 ffffffff 00cf9300 DPL=0 DS [-WA]
CS =0008 49000000 0008ffff 00589a00 DPL=0 CS32 [-R-]
SS =0010 00000000 ffffffff 00cf9300 DPL=0 DS [-WA]
DS =0010 00000000 ffffffff 00cf9300 DPL=0 DS [-WA]
FS =0010 00000000 ffffffff 00cf9300 DPL=0 DS [-WA]
GS =0010 00000000 ffffffff 00cf9300 DPL=0 DS [-WA]
LDT=0000 00000000 0000ffff 00008200 DPL=0 LDT
TR =0000 00000000 0000ffff 00008b00 DPL=0 TSS32-busy
GDT= 00103114 00000017
IDT= 00102900 000007ff
CR0=00000011 CR2=00000000 CR3=00000000 CR4=00000000
DR0=00000000 DR1=00000000 DR2=00000000 DR3=00000000
DR6=ffff0ff0 DR7=00000400
CCS=00000010 CCD=001031ce CCO=ADDL
EFER=0000000000000000
FCW=037f FSW=0000 [ST=0] FTW=00 MXCSR=00001f80
FPR0=0000000000000000 0000 FPR1=0000000000000000 0000
FPR2=0000000000000000 0000 FPR3=0000000000000000 0000
FPR4=0000000000000000 0000 FPR5=0000000000000000 0000
FPR6=0000000000000000 0000 FPR7=0000000000000000 0000
XMM00=00000000000000000000000000000000 XMM01=00000000000000000000000000000000
XMM02=00000000000000000000000000000000 XMM03=00000000000000000000000000000000
XMM04=00000000000000000000000000000000 XMM05=00000000000000000000000000000000
XMM06=00000000000000000000000000000000 XMM07=00000000000000000000000000000000
make: *** [Makefile:56: qemu] Aborted (core dumped)
我已经尝试过调试一段时间了。
另一个问题是它的变化....它不是一个稳定的错误，你可以在viedo上看到：https://www.youtube.com/watch?v=fHQE_vIu_wU&feature=youtu.be
答案 0 :(得分：2)
首先，您的重映射图片代码存在一些小问题：
example_string.replace("t", "b", 1)
master - ＆gt; 0x21（33）~0x28 奴隶 - ＆gt; 0x28~0x2f
正如您现在想象的那样，您实际上打算将master映射到0x20~0x27。但由于你有一个共同的IRQ处理程序，它并没有致命。
现在，对于崩溃，让我们跟踪IRQ的处理方式：
p8b_irq.out(0x21,PIC_MASTER_MASK);
p8b_irq.out(0x28,PIC_SLAVE_MASK);
（其后是cli和两次推送）irq0 common_handler_irq，基本上什么也没做。如果仔细查看堆栈，剩下两个推送，irq_handler将跳转到任何值 - 但不是简历地址。
你是如何获得＆＃34;尝试在RAM或ROM之外执行代码＆＃34;。
要修复它，请在iret之前相应地调整堆栈。
PS：还要注意iret没有使用适当的参数调用，* reg也是假的。