Question

我有一个xml文件如下所示，我希望从特定的日期（2017-01-01，在我的示例中）获得评分。但问题是他们中的一些人有多种费率，他们应该全部横向出来。格式没有问题，我可以根据xsl:stylesheet version="1.0"得到Rate1。但是我如何获得Rate2和Rate3？请帮助，这是一个例子。

这是xml：

<Table>
    <TableName>Table A</TableName>
    <Details>
        <Date>2016-01-01</Date>
        <Rate>0.01</Rate>
    </Details>
    <Details>
        <Date>2017-01-01</Date>
        <Rate>0.01</Rate>
    </Details>
</Table>
<Table>
    <TableName>Table B</TableName>
    <Details>
        <Date>2016-01-01</Date>
        <Rate>0.02</Rate>
    </Details>
    <Details>
        <Date>2017-01-01</Date>
        <Rate>0.02</Rate>
    </Details>
</Table>
<Table>
    <TableName>Table C</TableName>
    <Details>
        <Date>2016-01-01</Date>
        <Rate>0.03</Rate>
    </Details>
    <Details>
        <Date>2016-01-01</Date>
        <Rate>0.04</Rate>
    </Details>
    <Details>
        <Date>2016-01-01</Date>
        <Rate>0.05</Rate>
    </Details>
    <Details>
        <Date>2017-01-01</Date>
        <Rate>0.03</Rate>
    </Details>
    <Details>
        <Date>2017-01-01</Date>
        <Rate>0.04</Rate>
    </Details>
    <Details>
        <Date>2017-01-01</Date>
        <Rate>0.05</Rate>
    </Details>
</Table>

这是XSL：

<!--I have a variable defined $Date20170101 to get 2017-01-01-->
<xsl:if test="Details/Date = $Date20170101">
    <tr>
        <th>
            <xsl:value-of select="TableName"/>
        </th>
        <td>
            <!--"format-date" is to format the date to mm/dd/yyyy-->
            <xsl:call-template name="format-date">
                <xsl:with-param name="date">
                    <xsl:value-of select="Details/Date"/>
                </xsl:with-param>
            </xsl:call-template>
        </td>
        <!--Below is the problem I have-->
        <xsl:if test="(Details/Rate)[1]">
            <td>
                <xsl:value-of select="(Details/Rate)[1]"/>
            </td>
        </xsl:if>
        <xsl:if test="(Details/Rate)[2]">
            <td>
                <xsl:value-of select="(Details/Rate)[2]"/>
            </td>
        </xsl:if>
        <xsl:if test="(Details/Rate)[3]">
            <td>
                <xsl:value-of select="(Details/Rate)[2]"/>
            </td>
        </xsl:if>
    </tr>
</xsl:if>

以下是预期结果：

Table Name          Date        Rate1       Rate2       Rate3
Table A             1/1/2017    0.01        N/A         N/A
Table B             1/1/2017    0.02        N/A         N/A
Table C             1/1/2017    0.03        0.04        0.05

Answer 1

最高费率列将是3而不是更多

那么，它可以很简单：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/>

<xsl:param name="given-date">2017-01-01</xsl:param>

<xsl:template match="/root">
    <table border="1">
        <tr>
            <th>Table Name</th>
            <th>Date</th>
            <th>Rate1</th>
            <th>Rate2</th>
            <th>Rate3</th>
        </tr>
        <xsl:for-each select="Table">
            <tr>
                <td>
                    <xsl:value-of select="TableName"/>
                </td>
                <td>
                    <xsl:value-of select="$given-date"/>
                </td>
                <xsl:variable name="details" select="Details[Date=$given-date]" />
                <td>
                    <xsl:value-of select="$details[1]/Rate"/>
                </td>
                <td>
                    <xsl:value-of select="$details[2]/Rate"/>
                </td>
                <td>
                    <xsl:value-of select="$details[3]/Rate"/>
                </td>
            </tr>
        </xsl:for-each>
    </table>
</xsl:template>

</xsl:stylesheet>

当这适用于格式正确（！） XML输入时，例如：

<强> XML

<root>
    <Table>
        <TableName>Table A</TableName>
        <Details>
            <Date>2016-01-01</Date>
            <Rate>0.01</Rate>
        </Details>
        <Details>
            <Date>2017-01-01</Date>
            <Rate>0.01</Rate>
        </Details>
    </Table>
    <Table>
        <TableName>Table B</TableName>
        <Details>
            <Date>2016-01-01</Date>
            <Rate>0.02</Rate>
        </Details>
        <Details>
            <Date>2017-01-01</Date>
            <Rate>0.02</Rate>
        </Details>
    </Table>
    <Table>
        <TableName>Table C</TableName>
        <Details>
            <Date>2016-01-01</Date>
            <Rate>0.03</Rate>
        </Details>
        <Details>
            <Date>2016-01-01</Date>
            <Rate>0.04</Rate>
        </Details>
        <Details>
            <Date>2016-01-01</Date>
            <Rate>0.05</Rate>
        </Details>
        <Details>
            <Date>2017-01-01</Date>
            <Rate>0.03</Rate>
        </Details>
        <Details>
            <Date>2017-01-01</Date>
            <Rate>0.04</Rate>
        </Details>
        <Details>
            <Date>2017-01-01</Date>
            <Rate>0.05</Rate>
        </Details>
    </Table>
</root>

结果将是：

<table border="1">
   <tr>
      <th>Table Name</th>
      <th>Date</th>
      <th>Rate1</th>
      <th>Rate2</th>
      <th>Rate3</th>
   </tr>
   <tr>
      <td>Table A</td>
      <td>2017-01-01</td>
      <td>0.01</td>
      <td/>
      <td/>
   </tr>
   <tr>
      <td>Table B</td>
      <td>2017-01-01</td>
      <td>0.02</td>
      <td/>
      <td/>
   </tr>
   <tr>
      <td>Table C</td>
      <td>2017-01-01</td>
      <td>0.03</td>
      <td>0.04</td>
      <td>0.05</td>
   </tr>
</table>

呈现为：

XML - XSL从特定节点中选择并水平输出

1 个答案: