Question

我有以下应用程序用于发出以JSON格式返回数据的GET请求：

class Program
{
    static void Main(string[] args)
    {
        RunAsync().Wait();
    }

    static async Task RunAsync()
    {
        using (var client = new HttpClient())
        {
            //Send HTTP request
            client.BaseAddress = new Uri("httpMyURI");
            client.DefaultRequestHeaders.Accept.Clear();
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

            HttpResponseMessage response = await client.GetAsync("api/people/.....");

            if (response.IsSuccessStatusCode)
            {
                var person = response.Content.ReadAsAsync<IEnumerable<Persons>>().Result;

                foreach (var i in person)
                {
                    Console.WriteLine("{0}\t{1}-{2}", i.FirstName, i.LastName, i.Peopleid); 
                }
            }
        }
    }
}

class Persons
{
    public string Peopleid { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
}

如何根据我得到的结果创建xml文件？我想我首先必须将JSON转换为xml然后创建一个XML文件？

Answer 1

您可以使用Newtonsoft Json.NET库轻松完成此操作。请参阅操作中的示例：http://www.newtonsoft.com/json/help/html/convertingjsonandxml.htm

你所追求的是

XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(json);

Answer 2

保存xml文档非常简单

string responseAsString = response.Content.ReadAsStringAsync().Result; //Read response
XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(responseAsString); //Convert to XML
doc.Save("myfilename.xml"); //Save XML to file

从API响应创建xml

2 个答案: