我需要在一个有要求的网站上登录我,但我尝试过所有工作:
from bs4 import BeautifulSoup as bs
import requests
s = requests.session()
url = 'https://www.ent-place.fr/CookieAuth.dll?GetLogon?curl=Z2F&reason=0&formdir=5'
def authenticate():
headers = {'username': 'myuser', 'password': 'mypasss', '_Id': 'submit'}
page = s.get(url)
soup = bs(page.content)
value = soup.form.find_all('input')[2]['value']
headers.update({'value_name':value})
auth = s.post(url, params=headers, cookies=page.cookies)
authenticate()
或:
import requests
payload = {
'inUserName': 'user',
'inUserPass': 'pass'
}
with requests.Session() as s:
p = s.post('https://www.ent-place.fr/CookieAuth.dll?GetLogon?curl=Z2F&reason=0&formdir=5', data=payload)
print(p.text)
print(p.status_code)
r = s.get('A protected web page url')
print(r.text)
当我使用.status_code尝试此操作时,它会返回200,但我想要401或403来执行像#39;如果登录' ...
我找到了这个,但我认为它适用于python 2,但是我使用python 3而且我不知道如何转换......:
import requests
import sys
payload = {
'username': 'sopier',
'password': 'somepassword'
}
with requests.Session(config={'verbose': sys.stderr}) as c:
c.post('http://m.kaskus.co.id/user/login', data=payload)
r = c.get('http://m.kaskus.co/id/myform')
print 'sopier' in r.content
有人知道该怎么办?