我有一张包含以下数据的表格
ee2=> select * from emp;
id | name
----+---------------
1 | Hemant
2 | Hem-Awesome
3 | John A
4 | John B
5 | Hem-Awesome 2
6 | Hem-Awesome 3
7 | Hem-Awesome 4
(7 rows)
和相应的POJO
public class Employee {
private int id;
private String name;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
任务是查找名称与给定模式匹配且ID大于某个值的用户
此查询可实现所需的结果:
@Select("SELECT id, name from emp where name ilike '%${filter}%' and id > #{id}")
public List<Employee> listEmpByName(@Param("filter")String filter, @Param("id") int id);
17:28:40.742 [main] DEBUG c.e.d.m.FeedbackMapper.listEmpByName - ooo Using Connection [org.postgresql.jdbc4.Jdbc4Connection@1e257dea]
17:28:40.753 [main] DEBUG c.e.d.m.FeedbackMapper.listEmpByName - ==> Preparing: SELECT id, name from emp where name ilike '%hem%' and id > ?
17:28:40.801 [main] DEBUG c.e.d.m.FeedbackMapper.listEmpByName - ==> Parameters: 2(Integer)
17:28:40.836 [main] DEBUG c.e.d.m.FeedbackMapper.listEmpByName - <== Total: 3
[Employee [id=5, name=Hem-Awesome 2], Employee [id=6, name=Hem-Awesome 3], Employee [id=7, name=Hem-Awesome 4]]
但是,当我使用selectProvider时字符串替换失败。
@SelectProvider(type = com.hem.MapperSQLBuilder.class, method = "listEmpByNameProvider")
public List<Employee> listEmpByNameProvider(@Param("filter")String filter, @Param("id") int id);
select provider中的方法如下:
public String listEmpByNameProvider(Map<String, Object> parameters) {
System.out.println(parameters);
return "SELECT id, name from emp where name ilike '%${filter}%' and id > #{id}";
}
但是使用selectProvider,参数替换工作正常(#{})但是 字符串替换($ {})
17:35:40.146 [main] DEBUG o.a.i.t.jdbc.JdbcTransaction - Opening JDBC Connection
17:35:40.202 [main] DEBUG o.a.i.t.jdbc.JdbcTransaction - Setting autocommit to false on JDBC Connection [org.postgresql.jdbc4.Jdbc4Connection@7c6daa]
17:35:40.204 [main] DEBUG c.e.d.m.F.listEmpByNameProvider - ooo Using Connection [org.postgresql.jdbc4.Jdbc4Connection@7c6daa]
17:35:40.215 [main] DEBUG c.e.d.m.F.listEmpByNameProvider - ==> Preparing: SELECT id, name from emp where name ilike '%${filter}%' and id > ?
17:35:40.293 [main] DEBUG c.e.d.m.F.listEmpByNameProvider - ==> Parameters: 2(Integer)
17:35:40.338 [main] DEBUG c.e.d.m.F.listEmpByNameProvider - <== Total: 0
[]
有人可以将豆子溢出为何会发生这种情况吗?
答案 0 :(得分:0)
连接值,如下所示:
SELECT id, name from emp where name like '%"+${filter}+"%' and id > #{id}.