Question

在我的Android应用程序中，我有两个activity：

Player_List
Game_Launch

在第一个activity中，我问player的名称，如果所有名称都是空的，我们没有名字，但如果它们不是空的，我们会使用{{1} }。

当我添加4个玩家中的3个时，我players和activity。但是他添加了player的玩家。

如何制作empty？

Player_List：

check system

Game_Launch：

Intent i = new Intent(getApplicationContext(),Game_Launch.class);

            i.putExtra("player1", player1.getText().toString());
            i.putExtra("player2", player2.getText().toString());
            i.putExtra("player3", player3.getText().toString());
            i.putExtra("player4", player4.getText().toString());
            startActivity(i);

当我使用此检查时，它不起作用。你能帮我解决我的问题吗？谢谢。

编辑：

Intent in = getIntent();
        String player1= in.getExtras().getString("player1");
        String player2= in.getExtras().getString("player2");
        String player3= in.getExtras().getString("player3");
        String player4= in.getExtras().getString("player4");
        //Log.d();

        if (!player1.equals("")) {
            playerge= new String[] {"player2", "player3", "player4"};
        }
        else if (!player2.equals("")){
            playerge= new String[] {"player1", "player3", "player4"};
        }
        else if (!player3.equals("")){
            playerge= new String[] {"player1", "player2", "player4"};
        }
        else if (!player4.equals("")){
            playerge= new String[] {"player1", "player2", "player3"};
        }
        else if (!player1.equals("") && (!player2.equals(""))){
            playerge= new String[] {"player3", "player4"};
        }
        else if (!player3.equals("") && (!player4.equals(""))){
            playerge= new String[] {"player1", "player2"};
        }

My String 1已完成，2未完成，3已完成，4已完成，但我有P1吐司。

如何创建字符串：

With answerd i have tried :


Intent in = getIntent();
    String player1 = in.getStringExtra("player1");
    String player2 = in.getStringExtra("player2");
    String player3 = in.getStringExtra("player3");
    String player4 = in.getStringExtra("player4");

    //Log.d();

    if (!player1.equals("")) {
        playerge= new String[] {"player2", "player3", "player4"};
        Toast.makeText(getApplicationContext(), "p1", Toast.LENGTH_SHORT).show();
    }
     else if (!player2.equals("")) {
        playerge= new String[] {"player1", "player3", "player4"};
        Toast.makeText(getApplicationContext(), "p2", Toast.LENGTH_SHORT).show();
    }
    else if (!player3.equals("")) {
        playerge= new String[] {"player1", "player2", "player4"};
        Toast.makeText(getApplicationContext(), "p3", Toast.LENGTH_SHORT).show();
    }
    else if (!player4.equals("")) {
        playerge= new String[] {"player1", "player3", "player2"};
        Toast.makeText(getApplicationContext(), "p4", Toast.LENGTH_SHORT).show();
    }
        else{
            Toast.makeText(getApplicationContext(), "tout ok", Toast.LENGTH_SHORT).show();
        }

Answer 1

您收到的数据不正确。当您编写如下数据时：

Intent i = new Intent(getApplicationContext(), Game_Launch.class);
i.putExtra("player1", player1.getText().toString());

你得到它：

Intent in = getIntent();
String player1= in.getStringExtra("player1");

现在你可以按原样进行比较。

Answer 2

希望这有帮助。

if(player1.equalsIgnoreCase("") && (!TextUtil.isempty(player1)) )

获取数据如下：

Intent in = getIntent();
String player1= in.getStringExtra("player1");

检查字符串是否为空是不行的

2 个答案: