Question

我有一个按钮，当点击它将打开其他应用程序（如果您已经有应用程序）或向Windows商店（如果它没有应用程序）。但我有一个问题，那就是：当我有应用程序并单击按钮时，仅显示启动画面而无法打开应用程序。

XAML：

<Button x:Name="miBtn" Width="50" Height="50" Margin="25,0,0,0" Click="miBtn_Click" Style="{StaticResource ButtonStyle1}" BorderBrush="{x:Null}">
                            <Button.Background>
                                <ImageBrush Stretch="Uniform" ImageSource="image/new (3.0)/menu/menu bawah/MI-ikon-200.png"/>
                            </Button.Background>
                        </Button>

代码：

private async void miBtn_Click(object sender, RoutedEventArgs e)
        {
            var options = new Windows.System.LauncherOptions();
            options.PreferredApplicationPackageFamilyName = "MahoniGlobalPT.MajalahIndonesia_rm0rfdtcrak1p";
            options.PreferredApplicationDisplayName = "Majalah Indonesia";

            // Launch the URI and pass in the recommended app 
            var uriMI = new Uri("mi1:");
            // in case the user has no apps installed to handle the URI
            var success = await Windows.System.Launcher.LaunchUriAsync(uriMI, options);
        }

如何处理？

Answer 1

当我有应用程序并单击按钮时，仅显示启动屏幕，无法打开应用程序。

使用Windows.System.Launcher.LaunchUriAsync打开应用程序时。 OnLaunchedMethod内的目标应用App.xaml.cs将不会被触发。因此，不会为目标应用创建根帧。因此，您只能看到启动画面。

要解决此问题，您需要手动创建目标应用程序的根框架。您可以在Application.OnActivated中实现此目的：打开目标应用程序并在App.xaml.cs中添加以下代码：

private Frame CreateRootFrame()
{
    Frame rootFrame = Window.Current.Content as Frame;

    // Do not repeat app initialization when the Window already has content,
    // just ensure that the window is active
    if (rootFrame == null)
    {
        // Create a Frame to act as the navigation context and navigate to the first page
        rootFrame = new Frame();

        // Set the default language
        rootFrame.Language = Windows.Globalization.ApplicationLanguages.Languages[0];
        rootFrame.NavigationFailed += OnNavigationFailed;

        // Place the frame in the current Window
        Window.Current.Content = rootFrame;
    }

    return rootFrame;
}

更新：创建框架的过程应采用OnActivated方法：

protected override void OnActivated(IActivatedEventArgs args)
{
    var rootFrame = CreateRootFrame();
    rootFrame.Navigate(typeof(MainPage));//here navigate to typeof(YourPageName)
    Window.Current.Activate();
}

Answer 2

此示例对您有所帮助，请点击How to launch an UWP app from another app。

在您启动的应用中，您需要配置package.appxmanifest。以下XML是核心配置。

<Package> 
  <Applications> 
    <Application Id="App" Executable="$targetnametoken$.exe" EntryPoint="CSReceiveUri.App"> 
      <Extensions> 
        <uap:Extension Category="windows.protocol"> 
          <uap:Protocol Name="test-launchmainpage"> 
            <uap:DisplayName>test-launchmainpage</uap:DisplayName> 
          </uap:Protocol> 
        </uap:Extension> 
        <uap:Extension Category="windows.protocol"> 
          <uap:Protocol Name="test-launchpage1"> 
            <uap:DisplayName>test-launchpage1</uap:DisplayName> 
          </uap:Protocol> 
        </uap:Extension> 
      </Extensions> 
    </Application> 
  </Applications> 
</Package>

在已启动应用的app.cs中，您需要覆盖OnActivated事件处理程序，如下所示：

protected override void OnActivated(IActivatedEventArgs args)
{
    if (args.Kind == ActivationKind.Protocol)
    {
        Frame rootFrame = Window.Current.Content as Frame;

        if (rootFrame == null)
        {
            rootFrame = new Frame();
            Window.Current.Content = rootFrame;
            rootFrame.NavigationFailed += OnNavigationFailed;
        }

        //because this is in (args.Kind == ActivationKind.Protocol) block, so the type of args must is ProtocolActivatedEventArgs
        //convert to type ProtocolActivatedEventArgs, and we can visit Uri property in type ProtocolActivatedEventArgs
        var protocolEventArgs = args as ProtocolActivatedEventArgs;
        //Switch to a view by Scheme
        switch (protocolEventArgs.Uri.Scheme)
        {
            //under case is the protocol scheme in the Package.appxmanifest
            //Navigate to target page with Uri as parameter
            case "test-launchmainpage":
                rootFrame.Navigate(typeof(MainPage), protocolEventArgs.Uri);
                break;
            case "test-launchpage1":
                rootFrame.Navigate(typeof(Page1), protocolEventArgs.Uri);
                break;
            default:
                rootFrame.Navigate(typeof(MainPage), protocolEventArgs.Uri);
                break;
        }

        //start show UI
        Window.Current.Activate();
    }
}

启动到其他应用程序

2 个答案: