我试图做一个小游戏但是出现了一些奇怪的错误...
以下是代码:
while True:
print "======================MENU======================"
print "1 - Axali tamashis dawyeba:"
print "2 - Wesebi"
print "3 - Tamashis avtori"
menu = raw_input ("< ")
if menu == "3":
print "======================Avtori======================"
print ""
print ""
print "Tamashis avtoria - Sandro Stashevski"
elif menu == "2":
print "======================Wesebi======================"
print ""
print ""
print "Tamasshi aris 10 shekitxva. Tito shekitxvaze 4 savaraudo pasuxi."
print "Tqven agretve gaqvt 1 daxmareba: 50/50."
s11 == "A - Sidnei"
s12 == "B - Parizi"
s13 == "C - Berlini"
s14 == "D - Varshava"
daxmareba = "1 - 50/50 +"
elif menu == "1":
print "Shekitxva 1/10"
print ""
print "Ra hqvia Germaniis dedaqalaqs"
print s11,
print s12,
print s13,
print s14,
print ""
print daxmareba,
错误在第25行弹出...
elif menu == "1":
^
SyntaxError: invalid syntax
答案 0 :(得分:1)
您的代码存在一些缩进问题, 试试这个:
flash_video_player_url: false
答案 1 :(得分:1)
Python是一种缩进很重要的语言。它使用缩进来标识特定块的结束位置和新块的开始。
在上面的代码中,第25-29行不是一致缩进的。它应该与它上面的行具有相同的缩进(因为第30行上有另一个elif块)。此外,while True:
后面的行也必须缩进。
while True:
print "======================MENU======================"
print "1 - Axali tamashis dawyeba:"
print "2 - Wesebi"
print "3 - Tamashis avtori"
menu = raw_input ("< ")
if menu == "3":
print "======================Avtori======================"
print ""
print ""
print "Tamashis avtoria - Sandro Stashevski"
elif menu == "2":
print "======================Wesebi======================"
print ""
print ""
print "Tamasshi aris 10 shekitxva. Tito shekitxvaze 4 savaraudo pasuxi."
print "Tqven agretve gaqvt 1 daxmareba: 50/50."
s11 == "A - Sidnei"
s12 == "B - Parizi"
s13 == "C - Berlini"
s14 == "D - Varshava"
daxmareba = "1 - 50/50 +"
elif menu == "1":
print "Shekitxva 1/10"
print ""
print "Ra hqvia Germaniis dedaqalaqs"
print s11,
print s12,
print s13,
print s14,
print ""
print daxmareba,
还要确保使用一致的空格。不要混合空格和制表空格,这又会导致缩进错误。
答案 2 :(得分:0)
更一般的答案:
你有一个if ... elif ... elif ... else ...
构造。 Python期望每个if和else之间的部分(读elif
为else if
)作为一个块读取,可能还有进一步缩进的子块。所以你不应该
if True:
print 'foo'
print 'I am not indented enough'
elif False:
print 'I am never executed'
print 'I should be indented'
else:
print 'I am just as lonely as the elif stuff but at least I am indented'
我的代码的正确版本是:
if True:
print 'foo'
print 'I am not indented enough'
elif False:
print 'I am never executed'
print 'I should be indented'
else:
print 'I am just as lonely as the elif stuff but at least I am indented'