Question

我有以下查询

SELECT ID FROM MARMELADES mrm 
where not exists 
    (SELECT 1 FROM TOYS toys 
    WHERE mrm.ID = toys.ID 
    AND mrm.INGREDIENT = toys.INGREDIENT 
    AND mrm.BOX_TYPE = 2)
AND mrm.BOX_TYPE = 2

它会返回近400多个id结果，例如[12, 33, 45, ... , 3405]

现在，我想从我的数据库中删除该列表中的所有ID。这不仅仅是MARMELADES和TOYS。另外，我有35个以上的桌子，我可以有这个ID。

如果这个查询可以在ALL_UNNEEDED_IDS等函数中提取，我会很高兴，所以我可以像这样使用它：

DELETE FROM ANOTHER_TABLE_1 WHERE ID IN ( ALL_UNNEEDED_IDS ) 
DELETE FROM ANOTHER_TABLE_2 WHERE ID IN ( ALL_UNNEEDED_IDS ) 
DELETE FROM ANOTHER_TABLE_3 WHERE ID IN ( ALL_UNNEEDED_IDS ) 
DELETE FROM ANOTHER_TABLE_4 WHERE ID IN ( ALL_UNNEEDED_IDS ) 
...
DELETE FROM ANOTHER_TABLE_35 WHERE ID IN ( ALL_UNNEEDED_IDS )

可以在oracle中重复使用这样的结果吗？

Answer 1

在后续查询中使用第一个查询。 IE：

DELETE FROM ANOTHER_TABLE_1 WHERE ID IN (
     SELECT ID FROM MARMELADES mrm 
     where not exists 
         (SELECT 1 FROM TOYS toys 
         WHERE mrm.ID = toys.ID 
         AND mrm.INGREDIENT = toys.INGREDIENT 
         AND mrm.BOX_TYPE = 2)
     AND mrm.BOX_TYPE = 2
);

当你到达玩具和marmelades牌桌时，你需要一个临时的牌桌，正如@Gordon建议的那样。

重用select查询结果oracle

1 个答案: