Question

您好，我在服务器上运行应用程序时收到此错误消息：

Notice (8): Trying to get property of non-object [APP/Template/ApplicantEducationNeeds/view.ctp, line 52]

，这是view.ctp中的代码行：

    <?php

    use Cake\Cache\Cache;
    use Cake\Core\Configure;
    use Cake\Datasource\ConnectionManager;
    use Cake\Error\Debugger;
    use Cake\Network\Exception\NotFoundException;

    $this->layout = 'userProfile';

    if (!Configure::read('debug')):
        throw new NotFoundException();
    endif;

    //echo debug($applicantDesiredEducations);

    ?>

    <div class='col-md-12'>
        <div class="applicantGenerals view large-9 medium-8 columns content">

            <div class ='col-md-4'>
                <h3><?= __('Desired Education') ?></h3>
                    <table class="table">
                        <thead>
                            <tr>
                                <th><?= __('Field Of Studies') ?></th>
                                <th class="actions"><?= __('Actions') ?></th>
                            </tr>
                        </thead>
                        <tbody>
                            <?php foreach ($applicantDesiredEducations as $applicantDesiredEducation): ?>
                            <tr>
//here the lines of 50's
                                <td><?= $_language == 'en_US' ? h($applicantDesiredEducation->education_field_of_study_sub->name_en) : h($applicantDesiredEducation->education_field_of_study_sub->name_ara) ?></td>

但请注意，当我在本地机器中破坏此代码时，它的工作正常，任何有希望的解决方案都会降水

Answer 1

只是一个猜测，因为您没有提供有关您的错误的更多信息：

您正在循环浏览$applicantDesiredEducations，但可能不是每个$applicantDesiredEducation都有education_field_of_study_sub

因此，当您致电$applicantDesiredEducation->education_field_of_study_sub->name_en时，您会收到该错误

你必须检查房产的外观，例如

if(isset($applicantDesiredEducation->education_field_of_study_sub))
{
    echo h($applicantDesiredEducation->education_field_of_study_sub->name_en);   
}

cakePHP - 如何解决＆＃39;试图获得非对象的属性＆＃39;错误

1 个答案: