我有以下代码:
<ScrollViewer x:Name="swipeBetweenPages" Grid.Row="1">
<Pivot DataContext="{StaticResource ViewModel}" x:Name="pivot" Margin="0,-45,0,0"
HeaderTemplate="{StaticResource headerTest}"
ItemTemplate="{StaticResource pivotTemplate}" ItemsSource="{Binding Articles}" SelectionChanged="pivot_SelectionChanged">
</Pivot>
</ScrollViewer>
<Page.Resources>
<ViewModels:ArticleViewModel x:Key="ViewModel" />
<DataTemplate x:Key="headerTest">
</DataTemplate>
<DataTemplate x:Key="pivotTemplate">
<StackPanel Margin="-15 0 -15 0">
<Grid>
<Grid.Background>
<ImageBrush AlignmentX="Center" AlignmentY="Center" ImageSource="Assets/PlaceHolder.jpg"></ImageBrush>
</Grid.Background>
<Image q42controls:ImageExtensions.CacheUri="{Binding ImageURL}" Tag="{Binding ImageURL}" Tapped="ImageView"></Image>
</Grid>
<StackPanel Background="White">
<TextBlock x:Name="HeadLine" Text="{Binding HeadLine}"
Margin="10 5 0 -5" TextWrapping="Wrap"
FontSize="20" Foreground="Black"
FontFamily="{StaticResource HeadlineCommonFamiy}"
Pivot.SlideInAnimationGroup="GroupTwo" Height="63"
FontWeight="Bold" TextTrimming="CharacterEllipsis"/>
<TextBlock Text="{Binding Abstract}" TextWrapping="Wrap" FontSize="15" FontStyle="Italic"
Pivot.SlideInAnimationGroup="GroupTwo" Margin="10 5 0 10"
FontFamily="{StaticResource AbstractCommonFamily}"/>
</StackPanel>
<StackPanel x:Name="descriptionSP" Background="White">
<RichTextBlock IsTextSelectionEnabled="False" x:Name="richTextBlock"
local:Properties.Html="{Binding ArticleDetail}" TextWrapping="Wrap"
Pivot.SlideInAnimationGroup="GroupTwo" Margin="10 5 0 10"
FontFamily="{StaticResource ContentControlThemeFontFamily}">
</RichTextBlock>
</StackPanel>
</StackPanel>
</DataTemplate>
</Page.Resources>
如何在stackpanel中获取RichTextBlock控件?
现在,我正在尝试使用C#end中的以下代码:
private T FindElementInVisualTree<T>(DependencyObject parentElement) where T : DependencyObject
{
var count = VisualTreeHelper.GetChildrenCount(parentElement);
if (count == 0) return null;
for (int i = 0; i < count; i++)
{
var child = VisualTreeHelper.GetChild(parentElement, i);
if (child != null && child is T)
return (T)child;
else
{
var result = FindElementInVisualTree<T>(child);
if (result != null)
return result;
}
}
return null;
}
RichTextBlock richTextBlock = new RichTextBlock();
StackPanel rootStackPanel = new StackPanel();
StackPanel childStackPanel = new StackPanel();
PivotItem item = (sender as Pivot).ContainerFromItem((sender as Pivot).SelectedItem) as PivotItem;
rootStackPanel = item.ContentTemplate.LoadContent() as StackPanel;
childStackPanel = rootStackPanel.FindName("descriptionSP") as StackPanel;
richTextBlock = rootStackPanel.FindName("richTextBlock") as RichTextBlock;
Paragraph paragraph = new Paragraph();
Run run = new Run();
// Customize some properties on the RichTextBlock.
richTextBlock.IsTextSelectionEnabled = true;
richTextBlock.SelectionHighlightColor = new SolidColorBrush(Windows.UI.Colors.Pink);
richTextBlock.Foreground = new SolidColorBrush(Windows.UI.Colors.Blue);
richTextBlock.FontWeight = Windows.UI.Text.FontWeights.Light;
richTextBlock.FontFamily = new FontFamily("Arial");
richTextBlock.FontStyle = Windows.UI.Text.FontStyle.Italic;
richTextBlock.FontSize = 50;
//run.Text = "This is some sample text to demonstrate some properties.";
//Add the Run to the Paragraph, the Paragraph to the RichTextBlock.
paragraph.Inlines.Add(run);
richTextBlock.Blocks.Add(paragraph);
// Add the RichTextBlock to the visual tree (assumes stackPanel is decalred in XAML).
//childStackPanel.Children.Add(richTextBlock);
//rootStackPanel.Children.Add(richTextBlock);
但我无法获得控件RichTextBlock
。我得到null
值。
请帮我。
感谢。
答案 0 :(得分:3)
您可以使用ContentTemplate
的{{1}}来获取PivotItem
的模板,例如:
PivotItem
我首先给PivotItem item = (sender as Pivot).ContainerFromItem((sender as Pivot).SelectedItem) as PivotItem;
var rootStackPanel = item.ContentTemplate.LoadContent() as StackPanel;
var richtb = rootStackPanel.FindName("richtb") as RichTextBlock;
命名为&#34; richtb&#34;。
答案 1 :(得分:0)
您提供的代码会在树中搜索给定类型的第一个匹配控件。这意味着,您获得的回报是XAML定义中的第一个StackPanel
,而第二个中的RichTextBlock
。
为什么不直接这样做,而不是搜索StackPanel
:
var richTextBlock = FindElementInVisualTree<RichTextBlock>(item);
这将直接返回RichTextBlock
,因为FindElementInVisualTree
方法正在递归搜索树。