Question

是否可以这样做。我正在使用Yii 1.1

 public function rules()
        {
         return array(
                array('user_firstname, user_lastname, user_username, user_password,user_mobile,user_email', 'required','on'=>'createuser'),
             if ($this->user_role > 2 )
               {
                  array('user_special_permission, 'required'),    
                    }

                array('user_email, user_username, user_password', 'length', 'max'=>255),
                array('user_active, user_deleted', 'length', 'max'=>1),             
                // The following rule is used by search().
                // @todo Please remove those attributes that should not be searched.
                array('user_id, user_firstname, user_lastname, user_mobile, user_email, user_username, user_password, user_last_login, user_num_logins, user_num_failed_logins, user_active, user_deleted', 'safe', 'on'=>'search'),
            );
        }

仅在user_special_permission

时才需要required user_role >2

Answer 1

对于Yii 1.1，您可以在Model类中实现自定义验证规则，如下所示：

在rules数组中添加：

array('user_special_permission, 'role_validation'),

然后创建一个函数role_validation：

public function role_validation($attribute, $params)
{
     if ($this->user_role > 2 && empty($this->user_special_permission)) {
          $this->addError('user_special_permission','Special Permission required.');
     }
}

您可以调整显示错误消息的属性，而不是user_special_permission，例如user_role

有关更多文档，请参阅Declaring Validation Rules。

Answer 2

是的，在yii 1中是可能的你可以使用过滤器。代码将是

array('user_special_permission, 'required','when'=>function($model){ 
    return $model->user_role>2; 
 } 
),

仅在其他字段具有特殊值时是否必需？

2 个答案: