Question

我有几个用于过滤的网址。当我使用我得到的特定网址查找值时

api/v1/labels/?brand_city__location__state_or_country=New%20York
api/v1/labels/?brand_city__city=Novi%20Sad

使用的很多值在单词之间会有一个空格。如何从空格中删除%20并让网址更加清晰：

所需：api/v1/labels/?brand_city__city=Novi Sad没有%20在场

api.py

class LocationResource(ModelResource):
    class Meta:

        filtering =  {
            "state_or_country": ALL
        }

class CityResource(ModelResource):

    location = fields.ForeignKey(LocationResource, 'location', full=True)

    class Meta:

        filtering =  {
            "city": ALL,
            "location": ALL_WITH_RELATIONS
        }

class LabelResource(ModelResource):

    brand_city = fields.ForeignKey(CityResource, 'brand_city', full=True)

    class Meta:

        filtering = {
           "brand_category": ALL,
           "brand_city": ALL_WITH_RELATIONS
        }

代码段回复

{
  "labels": [
    {
      "brand_city": {
        "city": "Manhattan",
        "location": {
          "location_choices": "State",
          "state_or_country": "New York"
        }
      }
    }
  ],
  "meta": {
    "limit": 6,
    "next": null,
    "offset": 0,
    "previous": null,
    "total_count": 1
  }
}

Answer 1

查看python函数urllib2.unquote

# you can convert your urls using urlib2 library
path = urllib2.unquote("api/v1/labels/?brand_city__location__state_or_country=New%20York")

此外，与unquote一样，也可以使用另一个函数unquote_plus，它也可以按空格替换加号，这是取消引用HTML表单值所必需的。根据您的要求使用

从fillting url django tastypie中删除空格

1 个答案: