我想执行以下迁移:
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from django.contrib.auth.models import Permission
from django.db import migrations
from django.conf import settings
from django.contrib.auth.models import Group, User
def add_api_group(apps, schema_editor):
Group.objects.create(name=settings.API_USER_GROUP)
# get_or_create returns a tuple, not a Group
group = Group.objects.get(name=settings.API_USER_GROUP)
permissions = Permission.objects.filter(codename__in = [
'add_topic',
])
group.permissions.add(*permissions)
def add_api_user(apps, schema_editor):
user = User.objects.create_user(username=settings.API_USER, password=settings.API_USER_PASSWORD)
group = Group.objects.get(name=settings.API_USER_GROUP)
user.groups.add(group)
class Migration(migrations.Migration):
dependencies = [
('nd_content', '0001_initial'),
]
operations = [
migrations.RunPython(add_api_group),
migrations.RunPython(add_api_user)
]
在迁移的最后一行,我发出错误以停止执行并查看数据库状态。问题是表auth_permission
仍然没有另一个模块的模型的权限,尽管这个其他模块被注册为此迁移的依赖。
我可以确认只有在执行了所有迁移后才会添加丢失的权限。
答案 0 :(得分:13)
AttributeError: 'StateApps' object has no attribute 'label' in Django 1.10
有一个解决方案:
for app_config in apps.get_app_configs():
app_config.models_module = True
create_permissions(app_config, verbosity=0)
app_config.models_module = None
答案 1 :(得分:4)
编辑2018-01-31
此答案仅适用于Django 1.9。对于Django 1.10,请参考@ anton-lisenkov提供的answer
原始答案(Django< 1.10)
事实证明我可以做到以下几点:
from django.contrib.auth.management import create_permissions
def add_permissions(apps, schema_editor):
apps.models_module = True
create_permissions(apps, verbosity=0)
apps.models_module = None
谢谢@ elad-silver的回答:https://stackoverflow.com/a/34272647/854868
答案 2 :(得分:0)
如果您不必将许可权附加到个人模型,则可以通过以下方式做到这一点:
from django.contrib.auth.models import Permission, ContentType
def add_permission(apps, schema_editor):
content_type = ContentType.objects.get(app_label='auth', model='user') # I chose user model but you can edit it
permission = Permission(
name='Your permission description',
codename='your_codename',
content_type=content_type,
)
permission.save()