Question

我在JBPM 6.4中创建了一个新的存储库和一个新项目。在项目内部，我创建了一个persistence.xml：

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:orm="http://java.sun.com/xml/ns/persistence/orm" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd http://java.sun.com/xml/ns/persistence/orm http://java.sun.com/xml/ns/persistence/orm_2_0.xsd">
    <persistence-unit name="demox:com.prueba:1.0" transaction-type="JTA">
        <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
        <jta-data-source>java:jboss/datasources/jbpmDS</jta-data-source>
        <class>demox.com.prueba.Estudiante</class>
        <exclude-unlisted-classes>true</exclude-unlisted-classes>
        <properties>
            <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>
            <property name="hibernate.max_fetch_depth" value="3"/>
            <property name="hibernate.hbm2ddl.auto" value="update"/>
            <property name="hibernate.show_sql" value="false"/>
            <property name="hibernate.id.new_generator_mappings" value="false"/>
            <property name="hibernate.transaction.jta.platform" value="org.hibernate.service.jta.platform.internal.JBossAppServerJtaPlatform"/>
        </properties>
    </persistence-unit>
</persistence>

我还定义了一个可持续的对象（用@Entity装饰的pojo。）

现在我有一个只有一个脚本任务的简单流程。

但是当我在我的数据库中部署流程时，Student表已创建...

package demox.com.prueba;

/**
 * This class was automatically generated by the data modeler tool.
 */

@javax.persistence.Entity
public class Estudiante implements java.io.Serializable
{

   static final long serialVersionUID = 1L;

   @javax.persistence.GeneratedValue(strategy = javax.persistence.GenerationType.AUTO, generator = "ESTUDIANTE_ID_GENERATOR")
   @javax.persistence.Id
   @javax.persistence.SequenceGenerator(name = "ESTUDIANTE_ID_GENERATOR", sequenceName = "ESTUDIANTE_ID_SEQ")
   private java.lang.Long id;

   @org.kie.api.definition.type.Label(value = "name")
   private java.lang.String name;

   public Estudiante()
   {
   }

   public java.lang.Long getId()
   {
      return this.id;
   }

   public void setId(java.lang.Long id)
   {
      this.id = id;
   }

   public java.lang.String getName()
   {
      return this.name;
   }

   public void setName(java.lang.String name)
   {
      this.name = name;
   }

   public Estudiante(java.lang.Long id, java.lang.String name)
   {
      this.id = id;
      this.name = name;
   }

}

所以问题是：如何进入此scriptTask对此EntityManger的引用以保持此pojo？

我试过了：

demox.com.prueba.Estudiante est=new demox.com.prueba.Estudiante();
String pu="demox:com.prueba:1.0";

//javax.persistence.EntityManagerFactory emf = javax.persistence.Persistence.createEntityManagerFactory( pu );

javax.persistence.EntityManagerFactory emf = (javax.persistence.EntityManagerFactory) kcontext.getKnowledgeRuntime().getEnvironment()
                            .get(org.kie.api.runtime.EnvironmentName.ENTITY_MANAGER_FACTORY); # tried also EnvironmentName.CMD_SCOPED_ENTITY_MANAGER

System.out.println("Entity manager " + emf );

emf.persist(est);

但是当使用这段代码时，EntityManager是对JBPM持久性单元的引用，而不是我的持久性单元（demo）的实例，它不包含我的pojo类（未知实体）。

那么如何在我的脚本任务中访问这个持久性单元呢？

Answer 1

建议不要在script tasks中执行数据库调用等复杂操作。您应该使用service task代替您自己的work item handler实施。您已经可以使用自定义JPAWorkItemHandler实现。

项目上的JBPM 6.4持久性单元

1 个答案: