Question

我有3张桌子 - EVENT，MEMBER，RANK。对于特定事件（ex EVENT01），我需要显示最佳结果（来自RANK）及其所属成员（最简单的方法）是什么？我的下面的代码似乎选择了最小的数字，但重复自己并声称其他成员得到了相同的结果。

预期产出：

EVENT_ID    EVENT_TYPE    EVENT_NAME    MEMBER_ID    MEMBER_NAME    RESULT
event01     swimming      100m          mem001       John Smith     10

到目前为止

代码：

SELECT E.EVENT_ID, E.EVENT_TYPE, E.EVENT_NAME, R.MEMBER_ID, M.MEMBER_FIRSTNAME, M.MEMBER_LASTNAME, (SELECT MIN(RESULT)
FROM RANK WHERE E.EVENT_ID = 'EVENT003' ) AS AVG_INCOME_ALL_CLUBS
FROM EVENT E, RANK R, MEMBER M
WHERE E.EVENT_ID = R.EVENT_ID
AND R.MEMBER_ID = M.MEMBER_ID
ORDER BY MEMBER_ID;

Answer 1

首先，学会使用明确的JOIN语法。

其次，您的问题的答案是ROW_NUMBER()：

SELECT *
FROM (SELECT E.EVENT_ID, E.EVENT_TYPE, E.EVENT_NAME, R.MEMBER_ID, M.MEMBER_FIRSTNAME, M.MEMBER_LASTNAME,
             ROW_NUMBER() OVER (PARTITION BY E.EVENT_ID ORDER BY R.RESULT ASC) as SEQNUM
      FROM EVENT E, JOIN
           RANK R
           ON E.EVENT_ID = R.EVENT_ID JOIN
           MEMBER M 
           ON R.MEMBER_ID = M.MEMBER_ID
    ) ERM
WHERE SEQNUM = 1
ORDER BY MEMBER_ID;

Answer 2

 SELECT E.EVENT_ID, E.EVENT_TYPE, E.EVENT_NAME, R.MEMBER_ID,M.MEMBER_FIRSTNAME, M.MEMBER_LASTNAME,
 FROM EVENT E, JOIN
       RANK R
       ON E.EVENT_ID = R.EVENT_ID JOIN
       MEMBER M 
       ON R.MEMBER_ID = M.MEMBER_ID
       where R.RESULT=
 (SELECT MIN(RESULT) FROM RANK WHERE E.EVENT_ID = 'EVENT003') AND R.EVENT_ID='EVENT003';

从表格中的列中查找最小数字

2 个答案: