Question

因此，我尝试将我的位置过滤网址设为api/v1/labels/?brand_location=Australia，以过滤仅使用澳大利亚品牌的品牌，但仍会收到错误消息：

{"error": "Invalid resource lookup data provided (mismatched type)."}

但是当使用api/v1/labels/?brand_location/=Australia时它可以运行，但只过滤澳大利亚的位置，它会返回完全响应而不排除位置。

所以我的问题是：

如何删除斜杠？并让它过滤仅限澳大利亚的地点
这是正确的方法吗？使用带有django tastypie的外键吗？

我的代码如下：

的 Models.py

class Brand(models.Model):

    brand_location = models.ForeignKey('Location', null=True, blank=True, default="")


class Location(models.Model):

    state_or_country = models.CharField(unique=True, max_length=200, blank=True, default="", verbose_name=_('Location'),

api.py

class LocationResource(ModelResource):
    class Meta:
        excludes = ['modified', 'id', 'created']

        queryset = Location.objects.all()

        resource_name = 'locations'

class LabelResource(ModelResource):

    brand_location = fields.ForeignKey(LocationResource, 'brand_location', full=True)

    class Meta:

        filtering = {
            "brand_location": ALL
        }

        queryset = Brand.objects.all()

        resource_name = 'labels'

Snippet JSON响应

{
  "labels": [
    {
      "brand_location": {
        "state_or_country": "Australia"
      }
    }
  ],
  "meta": {
    "limit": 6,
    "next": "/unlabel-network/unlabel-network-api/v1/labels/?limit=6&brand_location%2F=Australia&offset=6",
    "offset": 0,
    "previous": null,
    "total_count": 128
  }
}

Answer 1

api/v1/labels/?brand_location=Australia查找Location.id=Australia。

允许过滤更深：

filtering = {
    "brand_location": ALL_WITH_RELATIONS
}

并查找state_or_country字段：

api/v1/labels/?brand_location__state_or_country=Australia

Answer 2

我只需要将filtering添加到我的LocationResource然后将ALL_WITH_RELATIONS添加到我的LabelResource

上的过滤字典中

class LocationResource(ModelResource):
    class Meta:
        excludes = ['modified', 'id', 'created']

        queryset = Location.objects.all()

        resource_name = 'locations'

        filtering =  {
            "state_or_country": ALL
        }

class LabelResource(ModelResource):

    brand_location = fields.ForeignKey(LocationResource, 'brand_location', full=True)

    class Meta:

        filtering = {
            "brand_location": ALL,
            "brand_location": ALL_WITH_RELATIONS
        }

        queryset = Brand.objects.all()

        resource_name = 'labels'

提供的资源查找数据无效（类型不匹配）

2 个答案: