Question

当我尝试从JSON响应中获取值时，我坚持了下来。这是我的代码

代码：

$.ajax({
    url: 'checkvotes.php',
    dataType: "json",
    success: function(data) {
     // want to fetch UP and DOWN variables from JSON here
     }
 });

来自PHP的AJAX响应

{"sample":[{"id":"1","message":"my message","up":"200","down":"34"}]}

Answer 1

$.ajax({
    url: 'checkvotes.php',
    dataType: "json",
    success: function(data) {
       var up = data.sample[0].up;
       var down = data.sample[0].down;
    }
 });

Answer 2

尝试data.sample[0].up和data.sample[0].down。如果有疑问，请使用此JavaScript来模拟调用：

var data = {"sample":[{"id":"1","message":"my message","up":"200","down":"34"}]};

在调试器中运行它并检查data。

Answer 3

var up = data['sample'][0]['up'],
    down = data['sample'][0]['down']

只需打印一个console.log（数据）来检查你的json

如何从AJAX响应中检索JSON变量

3 个答案: