Question

我需要一个解决方案，将一个字节的每个半字节转换为它的ASCII等价物。所以给出：

public class TestPrecedence {
    public static void main(String[] str) {
        int i = 0;
        System.out.println("\n");
        i = 2; System.out.println("i = " + i + "\n");
        i = 2; System.out.println("i++ = " + i++ + "\n");
        i = 2; System.out.println("++i = " + ++i + "\n");
        i = 2; System.out.println("i++i = (i++)i TestPrecedence.java:8: error: ')' expected\n"+
                                  "              i++i\n"+
                                  "                 ^\n");
        i = 2; System.out.println("i+-i = i+(-i) = " + (i+-i) + "\n");
        i = 2; System.out.println("++i++ = ++(i++) TestPrecedence.java:12: error: unexpected type\n"+
                                  "                ++i++ \n"+
                                  "                   ^\n"+
                                  "                required: variable\n"+
                                  "                found:    value\n");
        i = 2; System.out.println("i+++++i = ((i++)++)+i TestPrecedence.java:17: error: unexpected type\n"+
                                  "                      i+++++i\n"+
                                  "                       ^\n"+
                                  "                      required: variable\n"+
                                  "                      found:    value\n");
        i = 2; System.out.println("i++ + ++i = " + (i++ + ++i) + "\n");
        i = 2; System.out.println("i+(i=3) = " + (i+(i=3)) + " evaluates left to right\n");
        i = 2; System.out.println("i+i++ precedence yields i+(i++) evaluates to 2+2 = " + (i+i++) + "\n");
        i = 2; System.out.println("i+++i precedence yields (i++)+i evaluates to 2+3 = " + (i+++i) + "\n");
        System.out.println("\n");
    }
}

提前谢谢

Answer 1

只需将其转换为十六进制字符串并使用ASCII编码：

  byte varA = 0xAB;
  byte[] result = Encoding.ASCII.GetBytes(varA.ToString("x2"));
  // result[0] is 0x61
  // result[1] is 0x62

将半字节转换为ist ascii值

1 个答案: