Question

所以我一直在寻找如何使用QThreads和Signals的答案，并且得到了答案：

How to access GUI elements from another thread in PyQt

想知道这对其他人不起作用吗？窗户冻结了。我的电脑有什么问题或是答案吗？

代码是：

from PyQt4 import QtGui as gui
from PyQt4 import QtCore as core

import sys
import time


class ServerThread(core.QThread):
    def __init__(self, parent=None):
        core.QThread.__init__(self)

    def start_server(self):
        for i in range(1,6):
            time.sleep(1)
            self.emit(core.SIGNAL("dosomething(QString)"), str(i))

    def run(self):
        self.start_server()


class MainApp(gui.QWidget):
    def __init__(self, parent=None):
        super(MainApp,self).__init__(parent)

        self.label = gui.QLabel("hello world!!")

        layout = gui.QHBoxLayout(self)
        layout.addWidget(self.label)

        self.thread = ServerThread()
        self.thread.start()

        self.connect(self.thread, core.SIGNAL("dosomething(QString)"), self.doing)

    def doing(self, i):
        self.label.setText(i)
        if i == "5":
            self.destroy(self, destroyWindow =True, destroySubWindows = True)
            sys.exit()


app = gui.QApplication(sys.argv)
form = MainApp()
form.show()
app.exec_()

Answer 1

该代码适用于我Python 2.7.11 (v2.7.11:6d1b6a68f775, Dec 5 2015, 20:40:30) [MSC v.1500 64 bit (AMD64)] on win32。但是，该片段中有一个小错误：

您应该按此self.destroy(self, destroyWindow =True, destroySubWindows = True)更改此行self.destroy(destroyWindow =True, destroySubWindows = True)，否则您将收到此错误

TypeError：QWidget.destroy（bool destroyWindow = True，bool destroySubWindows = True）：参数1具有意外类型＆＃39; MainApp＆＃39;

pyqt QThread和Signal和Emit不适合这个答案

1 个答案: