Question

所以，我将一个对象传递给ES6函数，我希望 destructure 向下到参数的参数。例如，下面的代码会记录data的{{1}}道具，但我希望它能记录stuff things data道具stuff }。所以正确答案会记录[1,2,3,4]。我知道，根本不会混淆。有人知道这是否可行？

const stuff = {
   data: {
      things: [1,2,3,4]
   }
};
const getThings = ({ data }) => {
   console.log(data)    
};
getThings(stuff);

Answer 1

当然，这是如何：

public static void main(String[] args) throws FileNotFoundException {
  String treeString = "(ROOT (S (NP (NNP John)) (VP (VBZ eats) (NP (NN pizza))) (. .)))";
  Tree tree = Tree.valueOf(treeString);
  SemanticGraph graph = SemanticGraphFactory.generateUncollapsedDependencies(tree);

  //add lemmata
  Morphology morphology = new Morphology();
  for (IndexedWord node : graph.vertexSet()) {
    String lemma = morphology.lemma(node.word(), node.tag());
    node.setLemma(lemma);
  }

  System.err.println(graph);
  SemgrexPattern semgrex = SemgrexPattern.compile("{}=A <<dobj=reln {lemma:/eat/}=B");
  SemgrexMatcher matcher = semgrex.matcher(graph);
  while (matcher.find()) {
    System.err.println(matcher.getNode("A") + " <<dobj " + matcher.getNode("B"));
  }
}

Answer 2

正如我正确理解你的那样，正确答案是：

const getThings = ({ data: { things } }) => {
   console.log(things)    
};

构造一个对象参数两个级别？

2 个答案: