Question

查看我的代码，我试图将jquery.each中的所有值组合成这样的字符串，好，好，然后传递给ajax值。欣赏。或array('ok','good')也可以接受

var global = {
    "44":["onset","frequency"],
    "45":["onset"]
};
var $val = global[44];
            
jQuery.each( $val, function( key ,value) {		
    var value = $('#'+value).val();			
});
var $combine = ;//not sure how to combine all value like this (ok,good), or array(ok,good) acceptable also
var data= {
    action: 'check_first',
    AjaxFrontNonce : ajax_csky.AjaxFrontNonce,
    combine : $combine
}

<input type="hidden" id="onset" value="ok">
<input type="hidden" id="frequency" value="good">

Answer 1

试试这个：

＆＃13;

var global = {
    "44":["onset","frequency"],
    "45":["onset"]
};

var $val = global[44];
var values = [];  

jQuery.each( $val, function( key ,value) {		
    values.push($('#'+value).val());			
});

var $combine = '(' + values.join(',') + ')';
console.log($combine);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="hidden" id="onset" value="ok">
<input type="hidden" id="frequency" value="good">

＆＃13;

Answer 2

您可以使用$ .map覆盖所有项目并返回每个元素的值有一个Array和String值的示例，您可以使用哪个更适合您。

var global = {
    "44":["onset","frequency"],
    "45":["onset"]
};
var $val = global[44];

combinedAr = $.map($val, function(val) {
  return $('#'+val).val();
});
combinedStr = combinedAr.join(",");

var data= {
    action: 'check_first',
    AjaxFrontNonce : ajax_csky.AjaxFrontNonce,
    combine : combinedStr
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="hidden" id="onset" value="ok">
<input type="hidden" id="frequency" value="good">

Answer 3

试试这个工作代码段

var global = {
  "44": ["onset", "frequency"],
  "45": ["onset"]
};
var $val = global[44];
var arr = [];
$.each($val, function(key, val) {
  var value = $('#' + val).val();
  arr.push(value);
});

var $combine = arr; //not sure how to combine all value like this (ok,good), or array(ok,good) acceptable also
console.log($combine);
var data = {
  action: 'check_first',
  //AjaxFrontNonce : ajax_csky.AjaxFrontNonce, not defiend
  combine: $combine
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="hidden" id="onset" value="ok">
<input type="hidden" id="frequency" value="good">

试图结合jquery.each函数的所有值

3 个答案: