我有两个文件
文件1:
7118
7457
7591
7539
8001
文件2:
5003
5008
5011
5026
5028
5029
5031
我需要的输出
7118,5003
7457,5003
7591,5003
7539,5003
8001,5003
7118,5008
7457,5008
7591,5008
7539,5008
8001,5008
等等......
答案 0 :(得分:4)
awk 'FNR==NR{a[$0];next}{ for(i in a) print i,$0 }' OFS="," file file1
答案 1 :(得分:0)
我将使用perl脚本。
#!/usr/bin/perl
use strict;
my @file1 = loadf("file1.txt");
my @file2 = loadf("file2.txt");
foreach my $line2 (@file2) {
$line2 =~ s/^\s+//;
$line2 =~ s/\s+$//;
for (my $i = 0; $i < @file1; $i++) {
$file1[$i] =~ s/^\s+//;
$file1[$i] =~ s/\s+$//;
#do the output
print $file1[$i] . "," . $line2 . "\n";
}
}
sub loadf($) {
my @file = ( );
open(FILE, $_[0] . "\n") or die("[-] Couldn't Open " . $_[0] . "\n");
@file = <FILE>;
close(FILE);
return @file;
}
答案 2 :(得分:0)
还有一个bash函数:
function cross() {
exec 3<$2
while read -u 3 a ; do
exec 4<$1
while read -u 4 b ; do
echo $b,$a
done
done
3<&-
4<&-
}
答案 3 :(得分:0)
cat file1 | (exec 3< file2; while read A && read B <&3; do echo "$A,$B"; done)