我在MySQL中存储了一些看起来像这样的内容。
"Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.google.com"
当我在Golang模板中打印时,它无法正确解析。我的意思是一行显示所有内容。
它应该像这样打印
Hi!
How are you?
Here is the link you wanted:
http://www.google.com
这是我的模板代码。
<tr>
<td>TextBody</td>
<td>{{.Data.Content}}</td>
</tr>
我错过了什么吗?
答案 0 :(得分:3)
在这里,您可以使用Split函数来解析字符串,并使用sep
作为分隔符将子字符串拆分为片段。
package main
import (
"fmt"
"strings"
)
func main() {
txt := "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.google.com"
res := strings.Split(txt, "\n")
for _, val := range res {
fmt.Println(val)
}
}
输出将是:
Hi!
How are you?
Here is the link you wanted:
http://www.google.com
Go Playground上的示例。
答案 1 :(得分:1)
要在浏览器中打印此内容,请将[
{
url: "nigeria.php",
country: "Nigeria",
city_code: "ABV",
total_fare: "376",
arrival_to: "ABV"
},
{
url: "ghana.php",
country: "Ghana",
city_code: "ACC",
total_fare: "312",
arrival_to: "ACC"
},
{
url: "south-africa.php",
country: "South Africa",
city_code: "BFN",
total_fare: "432",
arrival_to: "BFN"
}
]
替换为例如\n
。 <br>
比如body = strings.Replace(body, "\n", "<br>", -1)
请参阅此工作示例代码:
package main
import (
"bytes"
"fmt"
"html/template"
"log"
"net/http"
"strings"
)
func main() {
http.HandleFunc("/", ServeHTTP)
if err := http.ListenAndServe(":80", nil); err != nil {
log.Fatal(err)
}
}
func ServeHTTP(w http.ResponseWriter, r *http.Request) {
html := `
<!DOCTYPE html>
<html>
<body>
<table style="width:100%">
<tr>
<th>Data</th>
<th>Content</th>
</tr>
<tr>
<td>{{.Data}}</td>
<td>{{.Content}}</td>
</tr>
</table>
</body>
</html>
`
st := "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.google.com"
data := DataContent{"data", st}
buf := &bytes.Buffer{}
t := template.Must(template.New("template1").Parse(html))
if err := t.Execute(buf, data); err != nil {
panic(err)
}
body := buf.String()
body = strings.Replace(body, "\n", "<br>", -1)
fmt.Fprint(w, body)
}
type DataContent struct {
Data, Content string
}
要查看输出,请运行此代码并在http://127.0.0.1/
另见:html/templates - Replacing newlines with <br>
我希望这会有所帮助。