有两个表可以一起使用。
第一张表:
AttendanceID TeacherID BatchID SubjectID SemesterID Date
32 110 8 9 1 2016-08-04
31 102 8 10 1 2016-07-17
30 108 6 22 3 2016-06-27
29 109 7 18 2 2016-06-27
28 109 8 13 1 2016-06-27
27 110 7 7 2 2016-06-27
26 110 8 9 1 2016-06-27
25 104 2 42 7 2016-04-20
24 104 5 35 5 2016-04-14
23 104 2 42 7 2016-04-14
22 102 2 41 7 2016-04-13
21 102 2 41 7 2016-04-10
20 102 6 23 3 2016-04-10
19 102 6 23 3 2016-04-10
第二张表:
第一个表由唯一的行组成,这些行将用于表2中的每个新的出勤列表。
例如:在第一个表格中,AttendanceID
21
用于第二个表格,用于完成特定主题的出席。
我想计算特定Subject
第二个表格中所有学生的百分比,并且可以通过第一个表AttendanceID
我在PHP中所做的是:首先,我使用此查询从第1个表中获取总数:
SELECT COUNT(AttendanceID) FROM attendances WHERE SubjectID = ? AND BatchID = ?"
一旦我从第一个表中获得特定主题和批次的出席总数,我将其存储在变量$total
中,然后我写了另一个查询,以便从第二个表中获得出席率:
SELECT COUNT(AttendanceDetailID) FROM attendancedetail WHERE CollegeID = ? AND Status = 'present' AND SubjectID = ?"
获得出席后我将其存储在变量$obtained
中
一旦我得到两个值,然后我用这样计算PHP中的百分比:
if(!empty($total) && !empty($obtained)) {
$result = (($obtained * 100)/ $total);
$result = round($result);
}
以下是PHP的完整代码:
public function showStateOfAttendance($subjectID, $batchID){
$st = $this->conn->prepare("SELECT CollegeID, Name, Gender, Photo FROM students WHERE BatchID = ?");
$st->bind_param("i", $batchID);
$st->execute();
$st->store_result();
$num_rows = $st->num_rows;
$st->bind_result($college_id, $name, $gender, $photo);
$this->response['attendance'] = array();
while($st->fetch()) {
$this->calcultaionOfAttendance($subjectID, $college_id, $name, $gender, $photo, $batchID);
}
return json_encode($this->response);
$st->free_result();
$st->close();
}
public function calcultaionOfAttendance($subjectID, $studentID, $name, $gender, $photo, $batchID) {
$stmt = $this->conn->prepare("SELECT COUNT(AttendanceID) FROM attendances WHERE SubjectID = ? AND BatchID = ?");
$stmt->bind_param("ii", $subjectID, $batchID);
$stmt->execute();
$stmt->store_result();
$num_rows = $stmt->num_rows;
$stmt->bind_result($AttendanceID);
while($stmt->fetch()) {
$total = $AttendanceID;
}
$stmt->free_result();
$stmt->close();
$stmt2 = $this->conn->prepare("SELECT COUNT(AttendanceDetailID) FROM attendancedetail WHERE CollegeID = ? AND Status = 'present' AND SubjectID = ?");
$stmt2->bind_param("ii", $studentID, $subjectID);
$stmt2->execute();
$stmt2->store_result();
$stmt2->bind_result($AttendanceDetailID);
while($stmt2->fetch()){
$obtained = $AttendanceDetailID;
}
if(!empty($total) && !empty($obtained)) {
$result = (($obtained * 100)/ $total);
$result = round($result);
$rating = ($result)/20;
$tmp = array();
$tmp['result'] = $result;
$tmp['total'] = $total;
$tmp['obtained'] = $obtained;
$tmp['rating'] = $rating;
$tmp['name'] = $name;
$tmp['college_id'] = $studentID;
$tmp['gender'] = $gender;
$tmp['photo'] = $photo;
array_push($this->response['attendance'],$tmp);
//var_dump(array($total, $obtained, $result, $rating, $studentID, $name));
}else if(empty($total)) {
$tmp = array();
$tmp['result'] = 0.0;
$tmp['total'] = 0.0;
$tmp['obtained'] = $obtained;
$tmp['rating'] = 0.0;
$tmp['name'] = $name;
$tmp['college_id'] = $studentID;
array_push($this->response['attendance'],$tmp);
//var_dump(array("0.0",$obtained, "0.0","0.0",$studentID,$name));
}else if(empty($obtained)) {
$tmp = array();
$tmp['result'] = 0.0;
$tmp['total'] = $total;
$tmp['obtained'] = 0.0;
$tmp['rating'] = 0.0;
$tmp['name'] = $name;
$tmp['college_id'] = $studentID;
array_push($this->response['attendance'],$tmp);
//var_dump(array($total, "0.0", "0.0","0.0", $studentID , $name));
}
}
以下是我所做查询的Android屏幕截图:以下结果适用于SubjectID = 23
和BatchID = 6
它为我提供了所需的结果,但我需要更好的方法来计算它,是否可以使用单个查询来执行此操作?
由于
答案 0 :(得分:1)
将查询放在子选择中:
SELECT
(SELECT COUNT(AttendanceDetailID) FROM attendancedetail WHERE CollegeID = ? AND Status = 'present' AND SubjectID = ?)
/ (SELECT COUNT(AttendanceID) FROM attendances WHERE SubjectID = ? AND BatchID = ?)
* 100
或(更易读)加入两个子查询:
SELECT (obtained * 100) / total
FROM (
SELECT COUNT(AttendanceDetailID) AS total
FROM attendancedetail
WHERE CollegeID = ? AND Status = 'present' AND SubjectID = ?
) t
CROSS JOIN (
SELECT COUNT(AttendanceID) AS obtained
FROM attendances
WHERE SubjectID = ? AND BatchID = ?
) a
答案 1 :(得分:1)
SELECT
SUM(`Status` = 'present') AS presentCount,
COUNT(*) AS totalCount,
(SUM(`Status` = 'present') * 100) / COUNT(*) AS percent
FROM
details
WHERE
BatchID = 2
AND SubjectID = 41
AND CollegeID = 1214
GROUP BY
AttendanceID
根据您的示例,您甚至无需访问第一个表格。您可以直接从第二个数据中计算出来。
答案 2 :(得分:1)
尝试:
SELECT s.CollectID, s.Name, s.Gender, s.Photo,
(SELECT count(AttendanceID) from attendances WHERE SubjectID =? and BatchID = s.BatchID) as total,
(SELECT count(AttendanceDetailID) FROM attendancedetail WHERE CollegeID = s.CollectID and Status = 'present' and SubjectID = ?) as obtained
FROM students s
WHERE s.BatchID = ?