Question

我有一张强制图表：

var canvas = document.querySelector("canvas"),
        context = canvas.getContext("2d"),
        width = canvas.width,
        height = canvas.height,
        min = 5;

var simulation = d3.forceSimulation()
        .force("link", d3.forceLink()
                .id(function(d) { return d.id; })
                .iterations(2)
                .distance(function(d) {
                    return Math.sqrt((600 - d.value)) / 10;
                })
                .strength(8)
        )
        .force("charge", d3.forceManyBody()
                .strength(-300)
                .theta(0.9)
                .distanceMax(400)
        )
        .force("center", d3.forceCenter(width / 2, height / 2)
        )
        .force("collision", d3.forceCollide(1))
        ;


d3.json("/contigderivatives/data/", function(error, graph) {
    if (error) throw error;

    simulation
            .nodes(graph.nodes)
            .on("tick", ticked);

    simulation.force("link")
            .links(graph.links);

    d3.select(canvas)
            .call(d3.drag()
                    .container(canvas)
                    .subject(dragsubject)
                    .on("start", dragstarted)
                    .on("drag", dragged)
                    .on("end", dragended));

    function ticked() {
        context.clearRect(0, 0, width, height);

        context.beginPath();
        graph.links.forEach(drawLink);
        context.strokeStyle = "#aaa";
        context.stroke();

        context.beginPath();
        graph.nodes.forEach(drawNode);
        context.strokeStyle = "#fff";
        context.fillStyle = 'steelblue';
        context.stroke();
        context.fill();
    }
    function dragsubject() {
        return simulation.find(d3.event.x, d3.event.y);
    }
});

function dragstarted() {
    if (!d3.event.active) simulation.alphaTarget(0.1).restart();
    d3.event.subject.fx = d3.event.subject.x;
    d3.event.subject.fy = d3.event.subject.y;
}

function dragged() {
    d3.event.subject.fx = d3.event.x;
    d3.event.subject.fy = d3.event.y;
}

function dragended() {
    if (!d3.event.active) simulation.alphaTarget(0);
    d3.event.subject.fx = null;
    d3.event.subject.fy = null;
}

function drawLink(d) {
    context.moveTo(d.source.x, d.source.y);
    context.lineTo(d.target.x, d.target.y);
}

function drawNode(d){
    d.x = Math.max(min, Math.min(width - min, d.x));
    d.y = Math.max(min, Math.min(height - min, d.y));
    context.moveTo(d.x + 3, d.y);
    context.arc(d.x, d.y, 3, 0, 2 * Math.PI);
}

我试图根据JSON中指定的分组来更改节点的颜色，该分组是一个整数，其中0 =红色，1 =蓝色。在使用SVG时，有很多关于如何更改节点样式的示例，但在使用画布时并不是很多。更改行context.fillStyle = 'steelblue';会更改所有节点的填充颜色。在使用画布时，如何更改单个节点的样式和属性？

Answer 1

我做了一个色标

 var color = d3.scaleOrdinal(d3.schemeCategory10);

然后在每个节点上根据节点数据属性绘制I颜色：

  function drawNode(d) {
    context.beginPath();//for each node do begin path as context fill style and stroke are different.
    context.moveTo(d.x + 3, d.y);
    context.arc(d.x, d.y, 3, 0, 2 * Math.PI);
    context.fillStyle = color(d.group);//coloring on the basis of the group
    context.strokeStyle = color(d.group);
    context.fill();
    context.stroke();
  }

根据你在评论中提到的bl.ock图，我做了一个小例子here

希望这可以解决您的问题。

更改d3.js强制节点画布布局中的节点组的颜色

1 个答案: