Question

我有以下代码来实现切换按钮。这样做的问题是，如果我点击切换按钮外部的左上角或左下角（仍然在边界矩形内），点击或检查操作将被触发，就像它是一个矩形一样。奇怪的是，这只发生在左侧，而不是右侧。

如何停止？

（要重新创建问题，请单击切换开关的左上角或左下角）

＆＃13;

.switch {
  position: relative;
  display: inline-block;
  width: 40px;
  height: 34px;
}
.switch input {
  display: none;
}
.slider {
  position: absolute;
  cursor: pointer;
  top: 0;
  left: 0;
  right: 0;
  bottom: 0;
  background-color: #ccc;
  -webkit-transition: .4s;
  transition: .4s;
}
.slider:before {
  position: absolute;
  content: "";
  height: 20px;
  width: 20px;
  left: 3px;
  bottom: 3px;
  background-color: white;
  -webkit-transition: .4s;
  transition: .4s;
}
input:checked + .slider {
  background-color: #2ECC71;
}
input:focus + .slider {
  box-shadow: 0 0 1px #2ECC71;
}
input:checked + .slider:before {
  -webkit-transform: translateX(25px);
  -ms-transform: translateX(25px);
  transform: translateX(25px);
}
/* Rounded sliders */

.slider.round {
  border-radius: 34px;
  height: 25px;
  width: 50px;
}
.slider.round:before {
  border-radius: 50%;
}

＆＃13;

<label class="switch">
  <input type="checkbox">
  <div id="utm-parameters-control" class="slider round accordion-control"></div>
</label>

＆＃13;

Answer 1

您可以使用class="switch"从标签中删除宽度和高度。这应该可以解决问题：

.switch {
    position: relative;
    display: inline-block;
    /* width: 40px; */
    /* height: 34px; */

Answer 2

删除label的高度和宽度，然后你去！

.switch {
  position: relative;
  display: inline-block;
}
.switch input {
  display: none;
}
.slider {
  position: absolute;
  cursor: pointer;
  top: 0;
  left: 0;
  right: 0;
  bottom: 0;
  background-color: #ccc;
  -webkit-transition: .4s;
  transition: .4s;
}
.slider:before {
  position: absolute;
  content: "";
  height: 20px;
  width: 20px;
  left: 3px;
  bottom: 3px;
  background-color: white;
  -webkit-transition: .4s;
  transition: .4s;
}
input:checked + .slider {
  background-color: #2ECC71;
}
input:focus + .slider {
  box-shadow: 0 0 1px #2ECC71;
}
input:checked + .slider:before {
  -webkit-transform: translateX(25px);
  -ms-transform: translateX(25px);
  transform: translateX(25px);
}
/* Rounded sliders */

.slider.round {
  border-radius: 34px;
  height: 25px;
  width: 50px;
}
.slider.round:before {
  border-radius: 50%;
}

<label class="switch">
  <input type="checkbox">
  <div id="utm-parameters-control" class="slider round accordion-control"></div>
</label>

Answer 3

如果您将label元素设为background-color，如下面的代码段所示，您将看到真正的“点击区域”。

.switch {
  background:red;
  position: relative;
  display: inline-block;
  width: 40px;
  height: 34px;
}
.switch input {
  display: none;
}
.slider {
  position: absolute;
  cursor: pointer;
  top: 0;
  left: 0;
  right: 0;
  bottom: 0;
  background-color: #ccc;
  -webkit-transition: .4s;
  transition: .4s;
}
.slider:before {
  position: absolute;
  content: "";
  height: 20px;
  width: 20px;
  left: 3px;
  bottom: 3px;
  background-color: white;
  -webkit-transition: .4s;
  transition: .4s;
}
input:checked + .slider {
  background-color: #2ECC71;
}
input:focus + .slider {
  box-shadow: 0 0 1px #2ECC71;
}
input:checked + .slider:before {
  -webkit-transform: translateX(25px);
  -ms-transform: translateX(25px);
  transform: translateX(25px);
}
/* Rounded sliders */

.slider.round {
  border-radius: 34px;
  height: 25px;
  width: 50px;
}
.slider.round:before {
  border-radius: 50%;
}

<label class="switch">
  <input type="checkbox">
  <div id="utm-parameters-control" class="slider round accordion-control"></div>
</label>

这说明了几个问题：

您的label比其子女高，
它比孩子还要窄，

其border-radius与其子项不匹配，因为它没有。{/ li>

要解决这些问题，您需要对CSS进行一些更改，例如以下代码段（我已将background-color保留在label上以进行可视化目的）：< / p>

.switch {
  background:red;
  border-radius:25px;
  position: relative;
  display: inline-block;
  width: 50px;
  height: 25px;
}
.switch input {
  display: none;
}
.slider {
  position: absolute;
  cursor: pointer;
  top: 0;
  left: 0;
  right: 0;
  bottom: 0;
  background-color: #ccc;
  -webkit-transition: .4s;
  transition: .4s;
}
.slider:before {
  position: absolute;
  content: "";
  height: 20px;
  width: 20px;
  left: 3px;
  bottom: 3px;
  background-color: white;
  -webkit-transition: .4s;
  transition: .4s;
}
input:checked + .slider {
  background-color: #2ECC71;
}
input:focus + .slider {
  box-shadow: 0 0 1px #2ECC71;
}
input:checked + .slider:before {
  -webkit-transform: translateX(25px);
  -ms-transform: translateX(25px);
  transform: translateX(25px);
}
/* Rounded sliders */

.slider.round {
  border-radius: 25px;
  height: 25px;
  width: 50px;
}
.slider.round:before {
  border-radius: 50%;
}

<label class="switch">
  <input type="checkbox">
  <div id="utm-parameters-control" class="slider round accordion-control"></div>
</label>

Answer 4

如下图所示，.switch类宽度在右侧不够宽。

screenshot of swift boundary

如果你将.slider.round宽度与.switch宽度匹配应该有效。我还调整了.switch类的高度，使其边界不超过。

.switch {
  position: relative;
  display: inline-block;
  width: 50px;
  height: 25px;
}

在div外部点击具有边界半径

4 个答案: