这是我用来从char数组构造字符串的演示代码,有没有更好的方法来构造String *RV200#
*FV200#
??
int main()
{
char String4H1[10] = "*FV";
char String4H3[10] = "*RV";
char String4H2[10] = "#";
char data1[10];
char data2[10];
snprintf(data1,4, "%03d", 200); //Convert integer to string function
snprintf(data2,4, "%03d", 200); //Convert integer to string function
ConvertToString(String4H1,data1, 3); //*FV200
ConvertToString(String4H3,data2, 3); //*RV200
ConvertToString(String4H1,String4H2,6); //*FV200#
ConvertToString(String4H3,String4H2,6); //*RV200#
//Display String4H1 And String 4H3
}
void ConvertToString(char subject[], const char insert[], int pos)
{
char buf[100] = {};
strncpy(buf, subject, pos); // copy at most first pos characters
int len = strlen(buf);
strcpy(buf+len, insert); // copy all of insert[] at the end
len += strlen(insert); // increase the length by length of insert[]
strcpy(buf+len, subject+pos); // copy the rest
strcpy(subject, buf); // copy it back to subject
// deallocate buf[] here, if used malloc()
}
在程序开始时不知道数字200
,它是使用IDE函数从内存中获取的,以从特定内存地址获取值。
像这样: -
unsigned short BUF = GetWord(@FrontVIB@,0);
unsigned short BUF1 = GetWord(@RearVIB@,0);
//BUF and BUF1 stores the value of address @FrontVIB@ and @RearVIB@ respectively
**structure** :-
unsigned short GetWord( @Address Alias@, Address Offset );
答案 0 :(得分:0)
这是一个简单的例子。可能我会被投票:)
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdbool.h>
bool concatenateString(char **dest, size_t *size, char *stringToAdd)
{
bool retVal = true;
char *dest_old = *dest;
*size += strlen(stringToAdd);
if (*dest == NULL)
{
*size += 1; // to add null terminator of string
*dest = calloc(1, size);
}
else
{
*dest = realloc(*dest, size);
}
if (dest == NULL)
{
free(dest_old);
retVal = false;
}
else
{
strcat(*dest, stringToAdd);
}
return retVal;
}
int main()
{
char newString[32] = {0};
int number;
size_t size = 0;
char *data1 = NULL;
printf("Insert a string:");
scanf(" %s", newString);
if (concatenateString(&data1, &size, newString))
{
printf("Insert a number:");
scanf(" %d", &number);
sprintf(newString, "%03d", number);
if (concatenateString(&data1, &size, newString) )
{
printf("Insert a string:");
scanf(" %s", newString);
if (concatenateString(&data1, &size, newString))
printf("%s\n", data1);
}
}
free(data1);
}
不使用动态分配
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdbool.h>
bool concatenateString(char *dest, size_t size_of_dest, char *stringToAdd)
{
bool retVal = true;
size_t new_size = strlen(dest) + strlen(stringToAdd);
if (new_size < size_of_dest)
{
strcat(dest, stringToAdd);
}
else
{
retVal = false;
}
return retVal;
}
int main()
{
char result[128] = {0};
char newString[32] = {0};
int number;
printf("Insert a string:");
scanf(" %s", newString);
printf("%s\n", newString);
if (concatenateString(result, sizeof(result), newString))
{
printf("Insert a number:");
scanf(" %d", &number);
sprintf(newString, "%03d", number);
if (concatenateString(result, sizeof(result), newString) )
{
printf("Insert a string:");
scanf(" %s", newString);
if (concatenateString(result, sizeof(result), newString))
printf("%s\n", result);
}
}
}
INPUT
Insert a string: *RV
Insert a number: 200
Insert a string: #
输出
*RV200#
答案 1 :(得分:0)
一些问题,我只处理ConvertToString()
尽管在处理字符串缓冲区问题方面做了一些尝试,但OP代码中存在太多漏洞。请考虑以下事项。
void ConvertToString(char subject[], const char insert[], int pos) {
char buf[100] = {};
strncpy(buf, subject, pos); // copy at most first pos characters
int len = strlen(buf);
...
pos == 100
有什么影响?
strlen(buf)
可能会尝试查找没有空字符的字符数组的长度 - &gt; UB。
pos > 100
有什么影响?
strncpy()
尝试在buf
。
迂腐:pos < 0
有什么影响?
strncpy()
尝试将buf
之外的数据写为pos
,将其转换为过大的无符号数。
关于strcpy(buf+len, subject+pos);
如果pos
超过strlen(subject)
,会产生什么影响
UB作为代码尝试在subject
之外读取。
重写尝试。关键元素:包括传入扩展subject
的可用大小并确定字符串长度。然后测试可接受性。完成所有操作后,转移subject
的结尾为insert
腾出空间。
void ConvertToString(char subject[], size_t subject_size, const char *insert,
size_t pos) {
size_t insert_length = strlen(insert);
size_t subject_length = strlen(subject);
// Insure pos does not exceed subject_length,
// this critical part missing in OP code
if (pos > subject_length) {
pos = subject_length;
}
// Insure we have enough space
size_t buf_size = subject_length + insert_length + 1;
if (buf_size > subject_size) {
Handle_Insufficent_subject_size();
return;
}
// Move end portion of `subject` over to the right `insert_length` places.
memmove(subject + pos + insert_length, subject + pos, subject_length - pos + 1);
memcpy(subject + pos, insert, insert_length); // copy insert
}