我尝试将数据发送到json文件中的数据表,如下: 例如我的json文件的数据:
"responseHeader":{
"status":0,
"QTime":2,
"params":{
"q":"vba",
"indent":"true",
"fl":"name,role_t,born,natio_t",
"wt":"json"}},
"response":{"numFound":7,"start":0,"docs":[
{
"name":"Khouli",
"born":["1978-04-03T00:00:00Z"],
"natio_t":"tunisien",
"role_t":"Consultant"},
{
"name":"Atayi",
"born":["1987-06-24T00:00:00Z"],
"natio_t":"Francaise",
"role_t":"Consultant"}
}
这是我的功能:
$ ( document ).ready(function() {
$.ajax({
type: 'GET',
url: '../search.json',
success: function(data) {
$.each(data, function(i, data) {
var body = "<tr>";
body += "<td>" + data.name + "</td>";
body += "<td>" + data.born + "</td>";
body += "<td>" + data.natio_t + "</td>";
body += "<td>" + data.role_t + "</td>";
body += "</tr>";
$('.datatable-ajax-source table').append(body);
});
如何从json文件中获取此值
答案 0 :(得分:0)
您的输入数据似乎有误:此处更正了数据:
{
"responseHeader":{
"status":0,
"QTime":2,
"params":{
"q":"vba",
"indent":"true",
"fl":"name,role_t,born,natio_t",
"wt":"json"}},
"response":{"numFound":7,"start":0,"docs":[
{
"name":"Khouli",
"born":["1978-04-03T00:00:00Z"],
"natio_t":"tunisien",
"role_t":"Consultant"},
{
"name":"Atayi",
"born":["1987-06-24T00:00:00Z"],
"natio_t":"Francaise",
"role_t":"Consultant"}
]
}
}
正确的JS来处理这个问题:
$(document).ready(function() {
$.ajax({
type: 'GET',
url: '../search.json',
success: function(data) {
// Data is the root node of your json response.
// You need to navigate through the "docs" node.
if(data.response.docs && data.response.docs.length > 0)
{
$.each(data.response.docs, function(i, item) {
var body = "<tr>";
body += "<td>" + item.name + "</td>";
body += "<td>" + item.born + "</td>";
body += "<td>" + item.natio_t + "</td>";
body += "<td>" + item.role_t + "</td>";
body += "</tr>";
$('.datatable-ajax-source table').append(body);
}
});
您没有获得data
的正确值。
您应该获得docs.data[i]
,在这种情况下,item
定义.each()
。
答案 1 :(得分:-2)
你没告诉jquery你期待json回来,所以它接受了服务器响应中的JSON字符串作为明文,并将其作为纯文本传递给data
。
使用.getJSON()
,它会将响应自动解析为本机JS数据结构,或者
$.ajax(
...
dataType: "json"
...
);