Question

我继承了一个表格（谁没有，对吧？），其数据如下所示：

Item          |             Properties        |        Quantity
--------------------------------------------------------------------
Shirt         |  button-down,polo,sleeveless  |          4,5,8

从短期来看，我想创建一个视图，但最终我想在时间允许的情况下将数据导出到新版本的表格中，并且更像是：

Item          |             Properties        |        Quantity
--------------------------------------------------------------------
Shirt         |            button-down        |            4   
Shirt         |               polo            |            5
Shirt         |             sleeveless        |            8

本质上，采用多个列组（我想会有其他表，其中列数多于两个具有这种行为的列）已知分隔符分隔并将它们分成不同的行？收集的任何其他行都不是这样的，在这个示例中将像Item一样共享。这些类型之间的逗号数量是统一的。

编辑：我使用了How to convert comma separated NVARCHAR to table records in SQL Server 2005?答案中给出的功能，这是我目前所拥有的：

select distinct data.item, tmptbl.[String] from
  data cross apply [ufn_CSVToTable](data.properties, ',') tmptbl ...

这适用于单列上下文，但是将该函数应用于第二列（在这种情况下为数量）可以直接生成属性和数量的所有可能组合，对吧？事实上，是的，它确实导致了我的尝试。似乎我需要一个光标或类似的东西来有效地分解属性的各个行[i] |数量[i]，将尝试构建它。那或者只是选择数据并在应用程序端将其拆分。

Answer 1

使用here ..

中的一个拆分字符串

如果您确定“属性”将始终具有与数量相同的计数（我的意思是属性中的3个值和数量中的3个值），那么您可以将下面的连接替换为内部连接...

;With cte
as
(select t.item ,a1.item as 'Properties',row_number() over (order by (select null)) as rownum1
 from #test t
cross apply
[dbo].[SplitStrings_Numbers](proper,',') a1
)
,cte1 as
(
select a2.item as quantity,row_number() over (order by (select null)) as rownum2
 from #test t
cross apply
[dbo].[SplitStrings_Numbers](quantity,',') a2
)
Select c.ite,c.Properties,c1.quantity
from cte c
full join
cte1 c1
on c.rownum1=c1.rownum2

输出

item    Properties  quantity
Shirt   button-down    4
Shirt   polo           5
Shirt   sleeveless     8

Answer 2

借助拆分器和交叉应用

Declare @YourTable table (item varchar(50),Properties varchar(50),Quantities varchar(50))
Insert into @YourTable values
('Shirt','button-down,polo,sleeveless','4,5,8')


Select A.item
      ,B.Properties
      ,B.Quantities
 From @YourTable A
 Cross Apply (Select Properties=A.Key_Value
                    ,Quantities=B.Key_Value
               From (Select * from [dbo].[udf-Str-Parse](A.Properties,',')) A
               Left Join (Select * from [dbo].[udf-Str-Parse](A.Quantities,',')) B on A.Key_PS=B.Key_PS 
 ) B

返回

item    Properties    Quantities
Shirt   button-down   4
Shirt   polo          5
Shirt   sleeveless    8

UDF

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimeter varchar(10))
--Usage: Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--       Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')
--       Select * from [dbo].[udf-Str-Parse]('id26,id46|id658,id967','|')
--       Select * from [dbo].[udf-Str-Parse]('hello world. It. is. . raining.today','.')

Returns @ReturnTable Table (Key_PS int IDENTITY(1,1), Key_Value varchar(max))
As
Begin
   Declare @XML xml;Set @XML = Cast('<x>' + Replace(@String,@Delimeter,'</x><x>')+'</x>' as XML)
   Insert Into @ReturnTable Select Key_Value = ltrim(rtrim(String.value('.', 'varchar(max)'))) FROM @XML.nodes('x') as T(String)
   Return 
End

Answer 3

CREATE FUNCTION [dbo].[ReturnTableOfVarchars]  
  (@IDList varchar(8000))  
    -- allow up to 256 varchar  
    RETURNS @IDTable table (RecordID varchar(256) NOT NULL)  
AS  
  BEGIN  
    DECLARE @IDListPosition int,   
      @ArrValue varchar(8000)  
    SET @IDList = COALESCE(@IDList,'')  
    IF @IDList<>''  
      BEGIN  
        -- add a comma to end of list  
        SELECT @IDList = @IDList+','  
        -- Loop through the comma delimited string list  
        WHILE PATINDEX('%,%',@IDList)<>0  
        BEGIN  
          -- find the position of the first comma in the list  
          SELECT @IDListPosition = PATINDEX('%,%',@IDList)  
          -- extract the string  
          SELECT @ArrValue = LEFT(@IDList, @IDListPosition - 1)  
          INSERT @IDTable (RecordID) VALUES(@ArrValue)  
          -- remove processed string  
          SELECT @IDList = STUFF(@IDList,1,@IDListPosition ,'')  
        END  
      END  
    RETURN  
  END

使用：

declare @itemvalues varchar(100) ,@itemcount varchar(100)
set @itemvalues='button-down,polo,sleeveless'
SET @itemcount =' 4,5,8'

select * from dbo.ReturnTableOfVarchars(@itemvalues)
select * from dbo.ReturnTableOfVarchars(@itemcount)

上面的函数会从字符串中拆分值，您可以根据您的过程插入select或update中的值。

将多个分隔符分隔的字段视为不同的行

3 个答案: