我已经创建了一个保存和加载文本文件数据的应用程序。我想要做的是搜索一个字符串,在WPF的适当位置显示该字符串以及两个字符串。 我认为它找到了正确的字符串,因为计数器正确显示,但没有任何字符串显示。这是我的搜索方法:
public void Search(string searchTerm)
{
var lineCount = File.ReadLines("products.txt").Count();
string line;
int counter = 0;
System.IO.StreamReader file = new System.IO.StreamReader("products.txt");
while ((line = file.ReadLine()) != null)
{
if (line.Contains(searchTerm))
{
break;
}
counter++;
}
textBlock.Text = counter.ToString();
string[] allLines = File.ReadAllLines("products.txt");
allLines[counter] = productNameBlock.Text;
allLines[counter + 1] = customerNameBlock.Text;
allLines[counter + 2] = firmwareBlock.Text;
}
任何想法?
答案 0 :(得分:3)
我认为你翻转了作业:
productNameBlock.Text = allLines[counter];
customerNameBlock.Text = allLines[counter + 1];
firmwareBlock.Text = allLines[counter + 2];
其次,你没有使用lineCount
所以只需删除那条额外的阅读线。
答案 1 :(得分:1)
为什么不使用我在your last question中提供的搜索功能?可以轻松完成这件事。总之...
public void Search(string searchTerm)
{
var allLines = File.ReadAllLines("products.txt");
int nonMatchingLineCount = allLines.Where(line => !line.Contains(searchTerm)).Count();
textBlock.Text = nonMatchingLines.Count().ToString();
productNameBlock.Text = allLines[counter];
customerNameBlock.Text = allLines[counter + 1];
firmwareBlock.Text = allLines[counter + 2];
}
答案 2 :(得分:1)
好像你有这个颠倒了
allLines[counter] = productNameBlock.Text;
allLines[counter + 1] = customerNameBlock.Text;
allLines[counter + 2] = firmwareBlock.Text;
如果你这样做会怎么样?
productNameBlock.Text = allLines[counter];
customerNameBlock.Text = allLines[counter + 1];
firmwareBlock.Text = allLines[counter + 2];