通过bash在单个CSV字段中替换额外的双引号

Question

我需要替换CSV日志文件中的额外双引号（字段以逗号分隔并用双引号引用）。替换必须仅影响CSV的最后一个字段。

输入日志文件示例：

"24-12-2015","23:07:08","00","01","00","00","START","00","END","JS786JGDG7899JSGJHG"dsdajasghsahd"

预期产出：

"24-12-2015","23:07:08","00","01","00","00","START","00","END","JS786JGDG7899JSGJHG''dsdajasghsahd"

我需要在bash或python中完成这项任务。

Answer 1

您可以使用awk：

awk "{gsub(/'/, \"''\", \$NF)} 1" file.csv

"24-12-2015","23:07:08","00","01","00","00","START","00","END","JS786JGDG7899JSGJHG''dsdajasghsahd"

Answer 2

试试这个;

awk -F, -v OFS="," '{gsub(/\"/,"\47\47",$NF)gsub(/^\47\47/,"\"",$NF);gsub(/\047\047$/,"\"",$NF) }1' file

"24-12-2015","23:07:08","00","01","00","00","START","00","END","JS786JGDG7899JSGJHG''dsdajasghsahd"