Question

我一直在寻找谷歌和本网站的解决方案。但我找不到合适的答案。我有一个json对象：

$scope.jsonObject = {
    "Card":{
          "type":"menu",
          "options":["option1","option2"],
          "name":"With card",
          "next":{
               "operations":{
                   "type":"menu",
                   "options":["option1","option2"],
                   "name":"Card Operations",
                   "next":{ 
                        "balance":{ 
                           "type":"transaction",
                           "options":["option1","option2"],
                           "name":"Get Balance",
                           "next":null           
                         },
                         "history":{ 
                           "type":"transaction",
                           "options":["option1","option2"],
                           "name":"History Card",
                           "next":null           
                         }
                   }

              }  
        }
   }
}

这是一个模板菜单，从这个菜单我需要创建带有角度foreach的新菜单：

$scope.sortMenu = {};
function sortObject(menu){
  angular.foreach(menu, function(key,value){
    if(key == "card"){
       $scope.sortMenu = menu;
    } 
    if(key == "history"){
       // I need delete object "history" from $scope.sortMenu    
    }
    sortObject(value.next);
  });
}
sortObject($scope.jsonObject);

如何从新菜单中删除“历史”对象？

谢谢你的回答。现在，我稍微改变了一下这个问题。这是浏览器中的$ scope.jsonObject：

这是一个菜单创建者：

function showDefaultMenu(menu,iterator){
            angular.forEach(menu, function(value, key){
                console.log(key);
                $('#myTree').append(
                    "<div class='col-md-12 col-xs-12'>" +
                    "<input type='checkbox' id='"+key+"' value='"+key+"' style='position: inherit;margin-left:"+iterator+"px'>"+key+
                    "</div>"
                );
                if(value.next !== undefined){
                    showDefaultMenu(value.next,iterator+20);
                }
            });
        }
        showDefaultMenu($scope.jsonObject,20);

这是html中的代码：

<div id="myTree" class="col-md-12 col-xs-12" style="margin-top: 50px;border:1px solid black;">
</div>
<div class="col-md-12 col-xs-12" style="margin-top: 10px;" >
     <input type="button" ng-click="constructNewMenu()" class="button btn-xs btn-info" value="Create Menu" />
</div>

这是constructNewMenu()而不是sortObject()：

function constructNewMenu(){
     assistantConstructMenu($scope.jsonObject);
}

function assistantConstructMenu(menu){
    angular.forEach(menu, function(value, key){
        if ($('#' + key).is(':checked')) {
            if (key === "card") {
                $scope.sortMenu.push(menu);
            }
        }else{
           // I need delete object "no checked" from $scope.sortMenu
        }
        if(value.next !== undefined){
            assistantConstructMenu(value.next);
        }
    });
}

如何删除“未选中”菜单，不知道他在对象层次结构中的级别？

Answer 1

你可以做

delete $scope.sortMenu.Card.next.operations.next.history;

或只是将其分配给空的json对象

$scope.sortMenu.Card.next.operations.next.history = {};

P.S。你的Json对象看起来很复杂。上述代码可能会出现can't get object of undefined错误。也许你可以通过null/undefined检查来逃避。

Answer 2

使用if(key == "history"){ delete $scope.sortMenu.Card.next.operations.next.history; }方法：

 @property (nonatomic, retain) NSMutableArray *array1;

了解更多信息，请阅读msdn delete

Answer 3

使用删除msdn

if(key == "history"){
   // I need delete object "history" from $scope.sortMenu    
   delete $scope.sortMenu.Card.next.operations.next.history;
}

了解更多信息，请阅读msdn delete

Answer 4

if（key ==＆＃34; history＆＃34;）{

   delete  $scope.sortMenu.Card.next.operations.next[key];

}

从Json对象中删除对象

如何从新菜单中删除“历史”对象？

4 个答案: