$this->db->select("*");
$this->db->from("panTab");
$this->db->where("QCJobPanelTestId = ",$TestId);
$query = $this->db->get();
$data['get_JobPan_Data'] = $query->result();
for($i = 0; $i < sizeof($data['get_JobPan_Data']);$i++)
{
$table = "Form1";
$whereField1 = "QC1TestId";
$whereField2 = "QC1JobPanelId";
$currDiv = "form1";
$this->db->select("*");
$this->db->from($table);
$this->db->where($whereField1." = ",$TestId);
$this->db->where($whereField2." = ",$data['get_JobPan_Data'][$i]['QCJobPanelId']); //--This value gives an error . How to access it?
$query1 = $this->db->get();
$data['getTestData'] = $query1->result();
}
即将推出的数据
Array (
[get_JobPan_Data] => Array (
[0] => stdClass Object(
[QCJobPanelId] => 293 [QCJobPanelNo] => 1
[QCJobPanelDesc] => Pan 1
[QCJobPanelJobId] => 3
[QCJobPanelPanelId] => 0
[QCJobPanelTestId] => 63
)
[getTestData] => Array (
[0] => stdClass Object (
[QC1Id] => 77
[QC1JobId] => 3
[QC1TestId] => 63
[QCTestDesc] => 0
[QC1DielectricACC_LC] => 0
[QC1DielectricACC_IRA] => 0
[QCRemark] => Completed
[QCTestedBy] => aa
[QCReviewedBy] => bb
[QCWitnessedBy] => cc
[QC1JobPanelId] => 293
[QCTestCompletionDate] => 2016-07-29 00:00:00
[QC1DateAdded] => 2016-07-29
)
)
)
也无法从$data['getTestData']
获取价值:
试过:
$data['getTestData'][0]['TestDesc']
$data['getTestData'][0][0]['TestDesc']
$data['getTestData']['TestDesc']
答案 0 :(得分:0)
回答获取$数据,包括来自@Anish&amp;的帮助@Anant:
简而言之:
- 如果是Array,则使用[]
- 如果是Object,则使用 - &gt;
答案 1 :(得分:0)
是的,访问对象有错误
let jsObj = {
"oid": "1",
"oname": "Fon",
"bun": [{
"bid": "1",
"bname": "Ets",
"dep": [{
"did": "1",
"dname": "Dptment",
"pids": [{
"pid": "1",
"st": "active"
}, {
"pid": "2",
"st": "active"
}]
}]
}, {
"bid": "2",
"bname": "US",
"description": "unit2",
"dep": []
}]
};
jsObj.bun.filter((b) => {
return b.bid == 1
});
替换为
$this->db->where($whereField2." = ",$data['get_JobPan_Data'][$i]['QCJobPanelId']);