Question

我想同时展示两个视频。以下代码正在运行，但不知何故，视频完成后会出现错误。如果我只播放一个视频，则不会发生错误。有什么帮助吗？

#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <iostream>

using namespace cv;
using namespace std;

int main()
{

    string filename1 = "C:/test_videos/toy_plane_liftoff.avi";
    string filename2 = "C:/test_videos/toy_plane_liftoff_stab.avi";

    VideoCapture capture1(filename1);
    VideoCapture capture2(filename2);

    Mat frame1, frame2;

    if (!capture1.isOpened())
        throw "Error1";
    if (!capture2.isOpened())
        throw "Error2";
    for (int i = 0; i <= min(capture1.get(CV_CAP_PROP_FRAME_COUNT), capture2.get(CV_CAP_PROP_FRAME_COUNT)); i++)
    {
        capture1 >> frame1;
        capture2 >> frame2;

        imshow("1", frame1);
        imshow("2", frame2);

        if (waitKey(30) >= 0) 
            break;
    }

    return 0;
}

Answer 1

您可以通过以下方式摆脱错误

HttpClient httpClient = new DefaultHttpClient();

try {
    HttpPost request = new HttpPost("https://invoice.zoho.com/api/v3/contacts?authtoken="ur_token"&organization_id="ur_org_id");
    StringEntity params =new StringEntity("JSONString={\"contact_name\":\"company_name\",\"age\":\"20\"} ");
    request.addHeader("content-type", "application/json");
    request.addHeader("Accept","application/json");
    request.setEntity(params);
    HttpResponse response = httpClient.execute(request);
    System.out.println(response);

    // handle response here...
}catch (Exception ex) {
    // handle exception here
} finally {
    httpClient.getConnectionManager().shutdown();
}

OpenCV同时播放2个视频

1 个答案: